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Possible Duplicate:
Regex for splitting a string using space when not surrounded by single or double quotes
我怎样才能打破这样的字符串:
String args = "\"file one.txt\" filetwo.txt some other \"things here\"";
在尊重引号的同时进入其参数/参数？
所以在上面的例子中，参数将被分解成:
args[0] = file one.txt
args[1] = filetwo.txt
args[2] = some
args[3] = other
args[4] = things here
我了解如何使用 split("")，但我想合并引号中的术语。
最佳答案
假设您不必使用正则表达式并且您的输入不包含嵌套引号，您可以在字符串字符的一次迭代中实现这一点:
String data = "\"file one.txt\" filetwo.txt some other \"things here\"";
List<String> tokens = new ArrayList<String>();
StringBuilder sb = new StringBuilder();
boolean insideQuote = false;
for (char c : data.toCharArray()) {
if (c == '"')
insideQuote = !insideQuote;
if (c == ' ' && !insideQuote) {//when space is not inside quote split..
tokens.add(sb.toString()); //token is ready, lets add it to list
sb.delete(0, sb.length()); //and reset StringBuilder`s content
} else
sb.append(c);//else add character to token
}
//lets not forget about last token that doesn't have space after it
tokens.add(sb.toString());
String[] array=tokens.toArray(new String[0]);
System.out.println(Arrays.toString(array));
输出:
["file one.txt", filetwo.txt, some, other, "things here"]
关于java - 如何根据引号将字符串分解为参数？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/14654540/