java - 如何检测和删除 URL 中的一句话？

Question

是否可以检测并删除句子中的任何类型的 URL？

例如:

Today,wheather is cold.But I want to out. http://weathers.com..... And I will take a cup of tea...

应该变成

Today,wheather is cold.But I want to out. And I will take a cup of tea...

Answer 1

这取决于您希望匹配过程的全面程度。您可以尝试使用像

这样简单的东西

str.replaceAll("http://[^\\s]+", "")

例如

System.out.println("Today,wheather is cold.But I want to out. "
        + "http://weathers.com..... And I will take a cup of tea..."
        .replaceAll("http://[^\\s]+", ""));

Today,wheather is cold.But I want to out.  And I will take a cup of tea...

---

如果您想要更强大的东西来匹配有效的 URL，请使用更完整的 URL 正则表达式:

/^(https?:\/\/)?([\da-z\.-]+)\.([a-z\.]{2,6})([\/\w \.-]*)*\/?$/

要获得更彻底的匹配，请参阅 this回答。