我正在尝试在 arrayList 中搜索用户输入指定的字符串,然后将搜索结果打印到控制台。我知道我应该使用 toIndex()
但我不知道如何对其进行语法分析。
import java.util.*;
public class searchSongs {
public static void main(String[]args){
Scanner searchBar = new Scanner(System.in);
System.out.println("Enter song title");
String search = searchBar.nextLine().toUpperCase();
for (int i = 0; i< MP3_catalogue.artist.size(); i++){
if (MP3_catalogue.artist.contains(search)){
int SV = search.indexOf(search);
System.out.println(MP3_catalogue.title.get(SV));
System.out.println(MP3_catalogue.artist.get(SV));
System.out.println(MP3_catalogue.duration.get(SV));
}
}
MP3_catalogue obj = new MP3_catalogue();
}
}
编辑:主类是包含数组列表的 MP3_catalogue。无需对其他 arrayLists 做任何特殊操作,它们具有与艺术家相同的索引值
import java.util.*;
public class MP3_catalogue {
static String gotoMenu = new String();
//"gotoMenu" is variable used to return to menu after each interaction with the methods.
public static ArrayList<String> title = new ArrayList<String>();
public static ArrayList<String> artist = new ArrayList<String>();
public static ArrayList<String> duration = new ArrayList<String>();
//arrayLists for song elements
@SuppressWarnings("resource")
public static void main(String[]args){
System.out.println("Welcome to your music catalogue. \n \n" + "Menu choices:");
System.out.println("A to add songs\n" + "D to delete songs\n" + "S to search catalogue\n" + "C to change song\n" + "? to shuffle catalogue\n");
gotoMenu = "Y";
while (gotoMenu.equals("Y")){
System.out.println("Enter your choice:");
Scanner userOption = new Scanner(System.in); //scanner to choose menu option
String choice = userOption.nextLine().toUpperCase();
switch (choice) {//switch statement used to go to each menu option
case "A": addSongs.main(args);//executes addSongs
System.out.println("Would you like to return to menu? Press Y to return, press N to exit program.");//choice to return to menu
String goback = userOption.nextLine().toUpperCase();
if(goback.equals("N"))
{
gotoMenu = "N";
}
break;
case "D": deleteSongs.main(args);
System.out.println("Would you like to return to menu? Press Y to return, press N to exit program.");//choice to return to menu
String returnMenu = userOption.nextLine().toUpperCase();
if(returnMenu.equals("N"))
{
gotoMenu = "N";
};
break;
case "S": searchSongs.main(args);
gotoMenu = "N";
break;
case "C": System.out.println("Change songs");
gotoMenu = "N";
break;
case "?": System.out.println("Shuffle time");
gotoMenu = "N";
break;
default: System.out.println("Doesn't match a menu choice. Type more carefully this time.");
break;
}
}
}
最佳答案
这就够了。不需要 for 循环..
if (MP3_catalogue.artist.contains(search)){
int SV = MP3_catalogue.artist.indexOf(search);
System.out.println(MP3_catalogue.title.get(SV));
System.out.println(MP3_catalogue.artist.get(SV));
System.out.println(MP3_catalogue.duration.get(SV));
} else {
System.out.println("not found");
}
关于java - 在数组列表中搜索字符串并打印该字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20211849/