更新 3:已解决!
问题与 FirebaseService、设置或负载无关。问题出在应用程序代码中......我们的代码有这样的东西(从应用程序继承):
ParentDroidApplication : Application
在该类的 OnCreate 方法中选择要使用的 Activity 并调用“StartActivity”。我将此开关移至 MainActivity,问题已解决。
更新 2:
Android list (已删除服务标签):
<manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.visma.vfsmobileparentapp" android:versionName="1.0" android:installLocation="internalOnly" android:versionCode="46">
<uses-sdk android:minSdkVersion="23" android:targetSdkVersion="26" />
<uses-permission android:name="android.permission.INTERNET" />
<application android:allowBackup="true" android:theme="@style/Theme.AppCompat.Light" android:label="Min skole" android:icon="@drawable/ic_launcher" android:name="Min skole">
<receiver android:name="com.google.firebase.iid.FirebaseInstanceIdInternalReceiver" android:exported="false" />
<receiver android:name="com.google.firebase.iid.FirebaseInstanceIdReceiver" android:exported="true" android:permission="com.google.android.c2dm.permission.SEND">
<intent-filter>
<action android:name="com.google.android.c2dm.intent.RECEIVE" />
<action android:name="com.google.android.c2dm.intent.REGISTRATION" />
<category android:name="${applicationId}" />
</intent-filter>
</receiver>
<meta-data android:name="com.google.firebase.messaging.default_notification_icon" android:resource="@drawable/ic_launcher" />
</application>
</manifest>
有效负载(添加了 content_available 和优先级):
{
"to" : "token",
"collapse_key" : "type_a",
"notification" : {
"body" : "First Notification",
"title": "Collapsing A"
},
"data" : {
"body" : "First Notification",
"title": "Collapsing A"
},
"content_available": true,
"priority": "high"
}
结果相同:应用程序在远程通知后自动打开 :(
更新:
我在 OnMessaggeReceive 方法中为我的主要 Activity 添加了 Intent 、默认声音和毫秒作为通知编号的整数(您可以在下面的代码中看到)。 我试过删除
<service android:name=".MyFirebaseMessagingService" android:stopWithTask="false">
<intent-filter>
<action android:name="com.google.firebase.MESSAGING_EVENT" />
</intent-filter>
</service>
我没有收到任何通知,但应用程序仍在打开。 Firebase 似乎正在正常工作。但是应用它会 self 施展魔法
我尝试将 Firebase 降级到版本 42.1021.1。结果是一样的
问题
我们正在使用 Xamarin 开发移动应用程序。我们需要通知,因此我们开始使用 Firebase 云消息传递。所有消息(通知)都在工作、接收,甚至在 iOS 中更新徽章,但是......Android 的一个问题:
如果应用已关闭(从应用列表中滑动)并收到远程通知,它会自动打开。我想避免这种情况。后台或前台模式按预期工作。
我的 Android list :
<manifest xmlns:android="http://schemas.android.com/apk/res/android" package="com.app" android:versionName="1.0" android:installLocation="internalOnly" android:versionCode="46">
<uses-sdk android:minSdkVersion="23" android:targetSdkVersion="26" />
<uses-permission android:name="android.permission.INTERNET" />
<application android:allowBackup="true" android:theme="@style/Theme.AppCompat.Light" android:label="App" android:icon="@drawable/ic_launcher" android:name="App">
<receiver android:name="com.google.firebase.iid.FirebaseInstanceIdInternalReceiver" android:exported="false" />
<receiver android:name="com.google.firebase.iid.FirebaseInstanceIdReceiver" android:exported="true" android:permission="com.google.android.c2dm.permission.SEND">
<intent-filter>
<action android:name="com.google.android.c2dm.intent.RECEIVE" />
<action android:name="com.google.android.c2dm.intent.REGISTRATION" />
<category android:name="${applicationId}" />
</intent-filter>
</receiver>
<meta-data android:name="com.google.firebase.messaging.default_notification_icon" android:resource="@drawable/ic_launcher" />
</application>
<service android:name=".MyFirebaseMessagingService" android:stopWithTask="true">
<intent-filter>
<action android:name="com.google.firebase.MESSAGING_EVENT" />
</intent-filter>
</service>
</manifest>
我的 FirebaseMessagingService.cs:
[Service]
[IntentFilter(new[] { "com.google.firebase.MESSAGING_EVENT" })]
public class MyFirebaseMessagingService : FirebaseMessagingService
{
public override void OnMessageReceived(RemoteMessage message)
{
SendNotification("title", "body"); //just for testing
}
public void SendNotification(string title, string body)
{
var intent = new Intent(this, typeof(LoginActivity));
var pendingIntent = PendingIntent.GetActivity(this, 0, intent, PendingIntentFlags.OneShot);
var defaultSoundUri = RingtoneManager.GetDefaultUri(RingtoneType.Notification);
var style = new Android.Support.V4.App.NotificationCompat.BigTextStyle();
style.BigText(body);
Bitmap largeIcon = BitmapFactory.DecodeResource(Resources, Resource.Drawable.ic_launcher);
var notificationBuilder =
new Android.Support.V4.App.NotificationCompat.Builder(this)
.SetLargeIcon(largeIcon)
.SetSmallIcon(Resource.Drawable.ic_launcher)
.SetContentTitle(title)
.SetContentText(body)
.SetStyle(style)
.SetAutoCancel(true)
.SetSound(defaultSoundUri)
.SetContentIntent(pendingIntent)
.SetVisibility((int)NotificationVisibility.Public);
var notificationManager = NotificationManager.FromContext(this);
notificationManager.Notify(DateTime.Now.Millisecond, notificationBuilder.Build());
}
}
我尝试更改 list 值、尝试模拟器、设备,我发送了不同的有效负载:
通知和数据:
{
"to" : "token",
"notification" : {
"body" : "First Notification",
"title": "Collapsing A"
},
"data" : {
"body" : "First Notification",
"title": "Collapsing A",
}
}
仅通知:
{
"to" : "token",
"notification" : {
"body" : "First Notification",
"title": "Collapsing A"
}
}
只有数据:
{
"to" : "token",
"data" : {
"body" : "First Notification",
"title": "Collapsing A"
}
}
在所有情况下,通知都会在应用关闭时自动接收和打开应用。如何避免自动打开?我只需要通知。有什么想法吗?
nuget 包:
Xamaring.Firebase.Messaging - 60.1142.1
Xamarin.Firebase.Code - 60.1142.1
Xamarin.Firebase.Common - 60.1142.1
在 Android 6 和 Android 7 设备(三星)上测试
最佳答案
你需要在这里定义Activity,它必须在你点击通知时打开。
var intent = new Intent(this, typeof(YourActivity));
intent.AddFlags(ActivityFlags.ClearTop);
//sent RemoteMessage message data to your activity if you need
//intent.PutExtra("User", JsonConvert.SerializeObject(user));
var pendingIntent = PendingIntent.GetActivity(this, GenerateRandom(), intent, PendingIntentFlags.OneShot);
var notificationBuilder = new Notification.Builder(this)
.SetSmallIcon(Resource.Drawable.myIcon)
.SetContentTitle(user.Organization)
.SetSubText(myModuleName)
.SetContentText(BodyText)
.SetAutoCancel(true)
.SetContentIntent(pendingIntent)
.Build();
var notificationManager = (NotificationManager)GetSystemService(Context.NotificationService);
var notification = RingtoneManager.GetDefaultUri(RingtoneType.Notification);
//this is for sound of notification
var mp = MediaPlayer.Create(ApplicationContext, notification);
mp.Start();
notificationManager.Notify(GenerateRandom(), notificationBuilder);
只为通知提供唯一的 Id,这样它们就不会重叠
private int GenerateRandom()
{
var rn = new Java.Util.Random();
int n = 1000 - 1233 + 1;
int i = rn.NextInt() % n;
return 1000 + i;
}
关于android - Xamarin Android 应用程序在收到远程通知时自动打开,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51999616/