java - Gradle:错误:程序类型已经存在:javax.inject.Inject

Question

我是 Android Studios 和 Gradle 的新手，所以如果这个问题很明显，我想道歉。

我收到给定代码的以下错误:

错误:程序类型已存在:javax.inject.Inject

apply plugin: 'com.android.application'

android {
    compileOptions {
        sourceCompatibility JavaVersion.VERSION_1_8
        targetCompatibility JavaVersion.VERSION_1_8
    }
    compileSdkVersion 28
    defaultConfig {
        applicationId "com.example.xxx.cryptoapp"
        minSdkVersion 15
        targetSdkVersion 28
        versionCode 1
        versionName "1.0"
        testInstrumentationRunner "android.support.test.runner.AndroidJUnitRunner"
    }
    buildTypes {
        release {
            minifyEnabled false
            proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
        }
    }
}

dependencies {
    implementation fileTree(dir: 'libs', include: ['*.jar'])
    implementation 'com.android.support:appcompat-v7:28.0.0'
    implementation 'com.android.support:design:28.0.0'
    implementation 'com.android.support.constraint:constraint-layout:1.1.3'
    implementation 'android.arch.lifecycle:extensions:1.1.1'
    testImplementation 'junit:junit:4.12'
    androidTestImplementation 'com.android.support.test:runner:1.0.2'
    androidTestImplementation 'com.android.support.test.espresso:espresso-core:3.0.2'
    compile 'com.lucadev:coinmarketcap-api:2.1'
}

希望你能帮帮我。 :)

编辑

我查看了依赖关系，发现 javax.inject 被使用了两次:

//short version of the list
+--- org.glassfish.hk2.external:javax.inject:2.5.0-b42@jar
+--- com.fasterxml.jackson.core:jackson-core:2.8.4@jar
    \--- javax.inject:javax.inject:1@jar

但是我不太明白如何排除正确的模块..

Answer 1

假设这是来自 libs 目录中的 .jar 文件；可以这样排除:

implementation (fileTree(dir: "libs", include: ["*.jar"])) {
    exclude group: "javax.inject", module: "javax.inject"
}

而实际上，.jar 可能应该被删除并替换为:

// https://mvnrepository.com/artifact/com.fasterxml.jackson.core/jackson-core
implementation ("com.fasterxml.jackson.core:jackson-core:2.9.8") {
    exclude group: "javax.inject", module: "javax.inject"
}

此存储库是 mavenCentral()。