android - 以编程方式创建的带有 LayerDrawable 的 StateListDrawable 不适用于 Android 4.0+

Question

我正在尝试创建一个带有彩色方 block 的选项组，供用户选择一个。它在 3.2 设备上工作，如下图所示:

代码是这样的:

for (int i = 0; i < COLORS.length; i++) {
        CheckBox box = new CheckBox(context);
        box.setBackgroundDrawable(getColorOption(context, COLORS[i]));
        box.setButtonDrawable(android.R.color.transparent);

然后，在 getColorOption 函数中我创建了 StateListDrawable:

    StateListDrawable slDrawable = new StateListDrawable();

    LayerDrawable checkedDrawable = new LayerDrawable(new Drawable[] {
            new SelectFrameShapeDrawable(transparentColor, lightRedColor),
            new SquareShapeDrawable(color) });
    LayerDrawable uncheckedDrawable = new LayerDrawable(new Drawable[] {
                    new SelectFrameShapeDrawable(transparentColor, transparentColor),
                    new SquareShapeDrawable(color) });
    slDrawable.addState(new int[] { android.R.attr.state_checked },
            checkedDrawable);
    slDrawable.addState(new int[] { -android.R.attr.state_checked }, uncheckedDrawable);
    return slDrawable;

SquareShapeDrawable 类是一个 ShapeDrawable:

public class SquareShapeDrawable extends ShapeDrawable {
    private final Paint fillpaint;

    public SquareShapeDrawable(int color) {
        super(new RectShape());
        fillpaint = new Paint(this.getPaint());
        fillpaint.setColor(color);
    }

    @Override
    protected void onDraw(Shape shape, Canvas canvas, Paint paint) {
        shape.draw(canvas, fillpaint);
    }
}

SelectFrameShapeDrawable 是:

private class SelectFrameShapeDrawable extends ShapeDrawable {
private final Paint fillpaint, strokepaint;

public SelectFrameShapeDrawable(int fill, int stroke) {
        super(new RectShape());
        strokepaint = new Paint(this.getPaint());
        strokepaint.setStyle(Paint.Style.STROKE);

        strokepaint.setStrokeWidth((int) (getResources()
                .getDisplayMetrics().density + 0.5f));
        strokepaint.setColor(stroke);
        int padding = (int) (4 * getResources().getDisplayMetrics().density + 0.5f);
        setPadding(padding, padding, padding, padding);

        fillpaint = new Paint(strokepaint);
        fillpaint.setColor(fill);
    }

    @Override
    protected void onDraw(Shape shape, Canvas canvas, Paint paint) {
        if (strokepaint != null)
            shape.draw(canvas, strokepaint);
        shape.draw(canvas, fillpaint);
    }
}

在 4.2 设备上，所有方 block 都是黑色的，并且在选中时不会改变:

问题似乎是在将可绘制对象添加到 StateListDrawable 时... 知道如何解决这个问题吗？

Answer 1

我通过删除扩展 ShapeDrawable 的自定义类并将它们替换为直接使用 ShapeDrawable 类的代码波纹管来解决黑色方 block 问题。此代码似乎适用于所有平台。

奇怪的是，最初的问题出现在 4.2 而不是 3.2。我最初的灵感来源是:http://www.betaful.com/2012/01/programmatic-shapes-in-android/

    ShapeDrawable selectFrame = new ShapeDrawable();
    selectFrame.setShape(new RectShape());
    selectFrame.getPaint().setColor(lightRedColor);
    selectFrame.getPaint().setStyle(Paint.Style.STROKE);
    selectFrame.getPaint().setStrokeWidth((int) (getResources().getDisplayMetrics().density + 0.5f));
    int padding = (int) (4 * getResources().getDisplayMetrics().density + 0.5f);
    selectFrame.setPadding(padding, padding, padding, padding);

    ShapeDrawable square = new ShapeDrawable();
    square.setShape(new RectShape());
    square.getPaint().setColor(color);

    LayerDrawable checkedDrawable = new LayerDrawable(new Drawable[] {
            selectFrame, square });
...