我创建了一个可展开的 ListView , subview 有复选框,当展开父 View 时,选中一个复选框,不仅会选中该复选框,还会选中另一个复选框。 我不知道为什么以及如何解决这个问题。 我在此链接中将源代码上传到 mediafire.com:
http://www.mediafire.com/?eih80athr56ejg2
这是MainActivity.java
public class MainActivity extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
SetListView();
}
private void SetListView(){
ExpandableListView lv=(ExpandableListView)findViewById(R.id.listview);
ExpAdapter adapter=new ExpAdapter(this);
lv.setAdapter(adapter);
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.activity_main, menu);
return true;
}
这是 ExpAdapter.java
public class ExpAdapter extends BaseExpandableListAdapter{
Context mContext;
int[][] data= new int[4][20];
public ExpAdapter(Context c){
mContext=c;
}
@Override
public Object getChild(int arg0, int arg1) {
// TODO Auto-generated method stub
return null;
}
@Override
public long getChildId(int arg0, int arg1) {
// TODO Auto-generated method stub
return 0;
}
@Override
public View getChildView(int groupPosition, int childPosition, boolean arg2, View convertView,
ViewGroup parent) {
// TODO Auto-generated method stub
if(convertView==null){
LayoutInflater inflater = (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
convertView = inflater.inflate(R.layout.childview,parent, false);
}
TextView tv=(TextView)convertView.findViewById(R.id.txtChild);
tv.setText("Child Position="+childPosition);
return convertView;
}
@Override
public int getChildrenCount(int arg0) {
// TODO Auto-generated method stub
return data[arg0].length;
}
@Override
public Object getGroup(int arg0) {
// TODO Auto-generated method stub
return null;
}
@Override
public int getGroupCount() {
// TODO Auto-generated method stub
return data.length;
}
@Override
public long getGroupId(int arg0) {
// TODO Auto-generated method stub
return 0;
}
@Override
public View getGroupView(int groupPosition, boolean arg1, View convertView, ViewGroup parent) {
// TODO Auto-generated method stub
if(convertView==null){
LayoutInflater inflater = (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
convertView = inflater.inflate(R.layout.groupview,parent, false);
}
TextView tv=(TextView)convertView.findViewById(R.id.txtGroup);
tv.setText("Group Position="+groupPosition);
return convertView;
}
@Override
public boolean hasStableIds() {
// TODO Auto-generated method stub
return false;
}
@Override
public boolean isChildSelectable(int arg0, int arg1) {
// TODO Auto-generated method stub
return false;
}
最佳答案
我已关注http://androidtrainningcenter.blogspot.in/2012/07/android-expandable-listview-simple.html
我们所需要的只是存储您的复选框的选中状态。我在 subview 的 xml 设计中添加了一个复选框并将其状态存储在 NewAdapter 中,以便当父 View 展开时我们可以恢复复选框状态。
在 NewAdapter 中完成的修改:
- 声明了一个名为 selectedNames 的字符串类型列表。
更改了 getChildView 方法实现,如下所示。
tempChild = (ArrayList<String>) Childtem.get(groupPosition); TextView text = null; if (convertView == null) { convertView = minflater.inflate(R.layout.childrow, null); } text = (TextView) convertView.findViewById(R.id.textView1); text.setText(tempChild.get(childPosition)); cb = (CheckBox) convertView.findViewById(R.id.cb_item); cb.setOnCheckedChangeListener(null); cb.setChecked(false); if (selectedNames.size() > 0 && selectedNames.indexOf(tempChild.get(childPosition)) != -1) { cb.setChecked(true); // Log.d("Present",tempChild.get(childPosition)); } cb.setOnCheckedChangeListener(new OnCheckedChangeListener() { public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) { if (isChecked) { int i = selectedNames.indexOf(tempChild.get(childPosition)); if (i == -1) { selectedNames.add(tempChild.get(childPosition)); } } else { int i = selectedNames.indexOf(tempChild.get(childPosition)); if (i != -1) { selectedNames.remove(i); } } } }); return convertView;
关于android - (Android需要帮助)复选框在可扩展 ListView 中自动疯狂检查,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13855349/