我在 AsyncTask 的 onpostexecute 方法中使用自定义对话框,它被弹出两次。当用户单击按钮时,必须关闭对话框,这似乎工作正常。
有人可以解释为什么它被调用两次吗?
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
if (pDialog != null) {
pDialog.dismiss();
}
try {
if (responseFromServer.contains("x")) {
// Pop up to create password
final Dialog dialog = new Dialog(getActivity());
dialog.setContentView(R.layout.dialog_password);
dialog.setTitle("Title...");
dialog.setCancelable(false);
final TextView etpassword = (TextView) dialog.findViewById(R.id.etpassword_dialog);
final Button btnpassword = (Button) dialog
.findViewById(R.id.btnsavepassword_dialog);
btnpassword.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
if (etpassword.getText().toString().length() == 0) {
Toast.makeText(getActivity(), "Enter password", Toast.LENGTH_SHORT)
.show();
} else if (etpassword.getText().toString().length() < 6) {
Toast.makeText(getActivity(),
"Password should contain minimmum 6 characters",
Toast.LENGTH_SHORT).show();
} else {
dialog.dismiss();
}
}
});
if (!dialog.isShowing()) {
dialog.show();
}
}
else {
Toast.makeText(getActivity(), "Unexpected error occurred. Please try again",
Toast.LENGTH_SHORT).show();
}
} catch (Exception e) {
Log.v("Main FRagment FB async::::::", e.getMessage());
}
}
最佳答案
您可以在显示自定义对话框之前编写以下条件,
if ( !dialog.isShowing() )
{
dialog.show();
}
关于android - 如何防止自定义对话框在 asynctask onPostExecute 中弹出两次?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21821318/