android - 嵌套 fragment : Detect click on outer fragment from within inner fragment

Question

我的应用程序有两个嵌套 fragment ，如下图所示:

如何从 Fragment2 实例中检测对 Fragment1 的点击？

Answer 1

即兴地说，我会说在 Fragment1 中创建一个监听器接口(interface)，然后在 Fragment2 中实现该接口(interface)并调用适当的方法在 Fragment1 的 onClick 方法的界面中。

编辑

这是一个非常简单的示例，我还没有测试过它，但这是一般理论。当然，您需要添加逻辑并填写必要的方法，例如 onCreate。

public class SampleActivity extends Activity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        // Initialize your activity here

        Fragment1 fragment1 = new Fragment1();
        Fragment2 fragment2 = new Fragment2();
        // Give fragment1 a reference to fragment2
        fragment1.registerListener(fragment2);
        // Do your fragment transactions here
    }
}

public class Fragment1 extends Fragment implements OnClickListener{

    // This is the interface. You can put as many abstract methods here as you want
    // with whatever parameters you want, but they all have to be overriden
    // in fragment2
    public interface FragmentClickListener {
        void onFragmentClick();
    }

    FragmentClickListener mListener;

    // This fragment needs to have a reference to the other fragment
    // This method can take any class that implements FragmentClickListener
    public void registerListener(FragmentClickListener mListener) {
        this.mListener = mListener;
    }

    @Override
    public void onClick(View view) {
        // You must check to make sure something is listening before you use the interface
        if (mListener != null) {
            //Let the interface know this fragment was clicked
            mListener.onFragmentClick();
        }
    }

}

public class Fragment2 extends Fragment implements FragmentClickListener {

    @Override
    public void onFragmentClick() {
        // Do whatever you want to do when fragment1 is clicked
    }

}