我正在编写一个应用程序,我希望能够将其打包到单个可执行 Jar 中,并使用嵌入式 Web 服务器来提供 REST API 和使用 API 的一组配置页面(允许 API由服务器外部的其他客户端访问,例如 Android 应用程序)。
到目前为止,我有一个基本的 REST API 可以正常工作,但在将它用于 View 时仍然遇到问题,我已尝试按照指南 here 进行操作并且无法获得解析为 JSP 页面的 View 名称。这里有一些日志行似乎表明它无法解决它:
15:37:23.559 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping - Looking up handler method for path /UserPage
15:37:23.560 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping - Did not find handler method for [/UserPage]
15:37:23.561 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.handler.SimpleUrlHandlerMapping - Matching patterns for request [/UserPage] are [/**]
15:37:23.561 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.handler.SimpleUrlHandlerMapping - URI Template variables for request [/UserPage] are {}
15:37:23.562 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.handler.SimpleUrlHandlerMapping - Mapping [/UserPage] to HandlerExecutionChain with handler [org.springframework.web.servlet.resource.ResourceHttpRequestHandler@37f9ecb0] and 1 interceptor
15:37:23.563 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.DispatcherServlet - Last-Modified value for [/UserPage] is: -1
15:37:23.564 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.resource.ResourceHttpRequestHandler - Trying relative path [UserPage] against base location: ServletContext resource [/]
15:37:23.564 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.resource.ResourceHttpRequestHandler - Trying relative path [UserPage] against base location: class path resource [META-INF/resources/]
15:37:23.565 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.resource.ResourceHttpRequestHandler - Trying relative path [UserPage] against base location: class path resource [resources/]
15:37:23.565 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.resource.ResourceHttpRequestHandler - Trying relative path [UserPage] against base location: class path resource [static/]
15:37:23.566 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.resource.ResourceHttpRequestHandler - Trying relative path [UserPage] against base location: class path resource [public/]
15:37:23.566 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.resource.ResourceHttpRequestHandler - No matching resource found - returning 404
我有一种感觉,因为我正在尝试使用嵌入式 Tomcat 服务器运行它(而不是将其部署到 Tomcat 服务器),所以我错过了配置 /webapp/
目录的步骤作为一个网络应用程序,但我对 Spring 还很陌生,所以我不确定我错过了什么。
src/main/webapp/web.xml:
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>IeNoTenshi</display-name>
<description>IeNoTenshi internal webserver</description>
<servlet>
<servlet-name>mvc-dispatcher</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>mvc-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/mvc-dispatcher-servlet.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
src/main/webapp/WEB-INF/mvc-dispatcher-servlet.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<context:component-scan base-package="com.dan_nixon.ienotenshi.web.service" />
<mvc:annotation-driven/>
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/pages/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
src/com/dan_nixon/.../web/service/UsersController.java
@Controller
@RequestMapping("/service")
public class UsersController {
private static final Logger log = LoggerFactory.getLogger(UsersController.class);
public static final int DEFAULT_COUNT = 10;
@RequestMapping(method=RequestMethod.GET)
public String test(ModelMap model) {
model.addAttribute("username", "test");
model.addAttribute("name", "Test User");
return "UserPage";
}
@RequestMapping(value="/user/{user_id}", method=RequestMethod.GET)
public @ResponseBody ModelAndView getUser(@PathVariable long user_id,
Model model) {
INTObjectDB db = new INTObjectDB();
db.open();
User user = db.getUser(user_id);
user.getPermissions();
db.close();
ModelAndView mav = new ModelAndView();
mav.setViewName("UserPage");
mav.addObject("username", user.getUsername());
mav.addObject("name", user.getName());
log.error(String.format("%s", mav));
return mav;
}
最佳答案
出现这个错误信息
15:37:23.559 [http-nio-8080-exec-1] DEBUG org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping - Looking up handler method for path /UserPage
看来你正在尝试访问类似的东西
localhost:8080/yourApp/UserPage
但是您显然没有映射到该 URL 的处理程序方法。您拥有的是映射到处理 GET 请求的 /service
的处理程序方法
@RequestMapping(method=RequestMethod.GET)
public String test(ModelMap model) {
model.addAttribute("username", "test");
model.addAttribute("name", "Test User");
return "UserPage";
}
您应该将请求发送至
localhost:8080/yourApp/service
关于java - Spring MVC 无法解析 View 名称,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20842070/