我有一个简单的应用程序，我在其中使用验证(效果很好)但是我在将错误消息传回表单时遇到问题。在示例中，我看到它看起来像是“神奇地”传递回表单，而无需手动设置任何属性或任何内容。
这是我的 Controller 代码:
@RequestMapping(value = "/createMember", method = RequestMethod.GET)
public ModelAndView showContacts() {
return new ModelAndView("createMember", "command", new Member());
}
@RequestMapping(value = "/createMember", method = RequestMethod.POST)
public ModelAndView addContact(@ModelAttribute("member")
@Valid Member member, BindingResult result) {
if(result.hasErrors()) {
return new ModelAndView("createMember", "command", member);
}
mba.addMember(member);
return getPages();
}
这是我的 createMember.jsp :
<%@taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core"%>
<%@taglib uri="http://www.springframework.org/tags/form" prefix="form"%>
<html>
<head>
<script src="<c:url value="/resources/core/jquery.1.10.2.min.js" />"></script>
<script src="<c:url value="/resources/core/jquery.autocomplete.min.js" />"></script>
<link href="<c:url value="/resources/core/main.css" />" rel="stylesheet">
</head>
<body>
<form:form method="post" action="createMember.html">
<table>
<tr>
<td><form:label path="firstName">First Name</form:label></td>
<td><form:input path="firstName" value="${member.firstName}" /></td>
<form:errors path="firstName" cssclass="error"></form:errors>
</tr>
<tr>
<td><form:label path="lastName">Last Name</form:label></td>
<td><form:input path="lastName" value="${member.lastName}" /></td>
<form:errors path="lastName" cssclass="error"></form:errors>
</tr>
<tr>
<td><form:label path="email1">Email</form:label></td>
<td><form:input value="${member.email1}" path="email1" /></td>
<form:errors path="email1" cssclass="error"></form:errors>
</tr>
<tr>
<td colspan="2">
<input type="submit" value="Add Contact"/>
</td>
</tr>
</table>
</form:form>
<a href="${pageContext.servletContext.contextPath}"> Back to main page </a>
</body>
</html>
我正在使用 Spring 3.2.2、Tomcat 7、hibernate-validator
验证类:
import javax.validation.constraints.Size;
import org.hibernate.validator.constraints.Email;
import org.hibernate.validator.constraints.NotEmpty;
public class Member {
private int memberID;
private int gender;
@Size(min=2, max=30)
private String firstName;
@Size(min=2, max=30)
private String lastName;
@NotEmpty @Email
private String email1;
//...getters and setters here
}
最佳答案
在 Controller 类中尝试使用 @ModelAttribute("command") 而不是 @ModelAttribute("member")。
关于java - 如何在 Spring 中将错误消息从 bean 传递到表单，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/22282620/