java - 为 servlet 分配异常 - JAVA 中的 Web 编程

Question

我对 JAVA 很陌生，但我在网络编程方面有一些经验。我正在创建简单的 jsp 页面并使用 @RequestMapping 进行页面浏览。但我遇到了一个异常(exception)，我用谷歌搜索但没有找到解决我问题的商品。 这是完整堆栈跟踪的异常:

SEVERE: Allocate exception for servlet [WebAppGraph] java.lang.ClassNotFoundException: com.WebAppGraph.app at org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1269) at org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1104) at org.apache.catalina.core.DefaultInstanceManager.loadClass(DefaultInstanceManager.java:508) at org.apache.catalina.core.DefaultInstanceManager.loadClassMaybePrivileged(DefaultInstanceManager.java:489) at org.apache.catalina.core.DefaultInstanceManager.newInstance(DefaultInstanceManager.java:119) at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1041) at org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:770) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:133) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:96) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:475) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:140) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:80) at org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:625) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:87) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:342) at org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:498) at org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:66) at org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:796) at org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1372) at org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49) at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617) at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61) at java.lang.Thread.run(Thread.java:745)

我的代码示例:

indexController.java

package com.WebAppGraph.app;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;

@Controller
public class indexController {

    @RequestMapping("/")
    public String home() {
        return "index.jsp";
    }

    @RequestMapping("/test.html")
    public String test() {
        return "test.jsp";
    }

}

Web.xml

<!DOCTYPE web-app PUBLIC
 "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
 "http://java.sun.com/dtd/web-app_2_3.dtd" >

<web-app>
    <display-name>Archetype Created Web Application</display-name>
    <servlet>
        <servlet-name>WebAppGraph</servlet-name>
        <servlet-class>
            com.WebAppGraph.app
        </servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>WebAppGraph</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
</web-app>

WebAppGraph-servlet.xml

<?xml version="1.0" encoding="UTF-8" ?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context-3.0.xsd
        http://www.springframework.org/schema/mvc
        http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">

    <context:component-scan base-package="com.WebAppGraph.app"></context:component-scan>

</beans>

POM.xml

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <groupId>com.WebAppGraph.app</groupId>
    <artifactId>WebAppGraph</artifactId>
    <packaging>war</packaging>
    <version>1.0</version>
    <name>WebAppGraph Maven Webapp</name>
    <url>http://maven.apache.org</url>
    <dependencies>
        <dependency>
            <groupId>junit</groupId>
            <artifactId>junit</artifactId>
            <version>3.8.1</version>
            <scope>test</scope>
        </dependency>
        <!-- https://mvnrepository.com/artifact/org.springframework/spring-webmvc -->
        <dependency>
            <groupId>org.springframework</groupId>
            <artifactId>spring-webmvc</artifactId>
            <version>4.3.10.RELEASE</version>
        </dependency>
        <dependency>
            <groupId>javax.servlet</groupId>
            <artifactId>javax.servlet-api</artifactId>
            <version>3.0.1</version>
            <scope>provided</scope>
        </dependency>
    </dependencies>
    <build>
        <finalName>WebAppGraph</finalName>
    </build>
</project>

文件结构:

当我尝试运行我的程序时，它会打开 index.jsp 页面，但第二个页面仅在我编写 localhost:9000/WebAppGraph/test.jsp 时打开但是，当我编写 localhost:9000/WebAppGraph/test.html 时，它不会向我显示 test.jsp，而是向我显示我在上面发布的异常。 知道如何解决这个问题吗？

Answer 1

对于您的 servlet 映射，您可以在 web.xml 中执行类似的操作:

<servlet>
    <servlet-name>WebAppGraph</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/WebAppGraph-servlet.xml</param-value>
    </init-param>
</servlet>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet-mapping>
    <servlet-name>WebAppGraph</servlet-name>
    <url-pattern>*.html</url-pattern>
    <url-pattern>/</url-pattern>
</servlet-mapping>