我需要将 CSV 文件的列中的许多日期从 dd/mm/yyyy 格式转换为 yyyy-mm-dd 格式。例如,17/01/2010 应转换为 2010-01-17。
我如何在 Perl 或 Python 中执行此操作?
最佳答案
如果保证您的数据格式正确,只包含 DD-MM-YYYY 格式的单例日期,那么这行得通:
# FIRST METHOD
my $ndate = join("-" => reverse split(m[/], $date));
这适用于持有“07/04/1776”的$date
,但在“this 17/01/2010 and that 01/17/2010 there”上失败。相反,使用:
# SECOND METHOD
($ndate = $date) =~ s{
\b
( \d \d )
/ ( \d \d )
/ ( \d {4} )
\b
}{$3-$2-$1}gx;
如果您更喜欢更“符合语法”的正则表达式,以便更容易维护和更新,您可以改用这个:
# THIRD METHOD
($ndate = $date) =~ s{
(?&break)
(?<DAY> (?&day) )
(?&slash) (?<MONTH> (?&month) )
(?&slash) (?<YEAR> (?&year) )
(?&break)
(?(DEFINE)
(?<break> \b )
(?<slash> / )
(?<year> \d {4} )
(?<month> \d {2} )
(?<day> \d {2} )
)
}{
join "-" => @+{qw<YEAR MONTH DAY>}
}gxe;
最后,如果您有 Unicode 数据,您可能需要更加小心。
# FOURTH METHOD
($ndate = $date) =~ s{
(?&break_before)
(?<DAY> (?&day) )
(?&slash) (?<MONTH> (?&month) )
(?&slash) (?<YEAR> (?&year) )
(?&break_after)
(?(DEFINE)
(?<slash> / )
(?<start> \A )
(?<finish> \z )
# don't really want to use \D or [^0-9] here:
(?<break_before>
(?<= [\pC\pP\pS\p{Space}] )
| (?<= \A )
)
(?<break_after>
(?= [\pC\pP\pS\p{Space}]
| \z
)
)
(?<digit> \d )
(?<year> (?&digit) {4} )
(?<month> (?&digit) {2} )
(?<day> (?&digit) {2} )
)
}{
join "-" => @+{qw<YEAR MONTH DAY>}
}gxe;
您可以看到这四种方法在遇到如下示例输入字符串时的表现如何:
my $sample = q(17/01/2010);
my @strings = (
$sample, # trivial case
# multiple case
"this $sample and that $sample there",
# multiple case with non-ASCII BMP code points
# U+201C and U+201D are LEFT and RIGHT DOUBLE QUOTATION MARK
"from \x{201c}$sample\x{201d} through\xA0$sample",
# multiple case with non-ASCII code points
# from both the BMP and the SMP
# code point U+02013 is EN DASH, props \pP \p{Pd}
# code point U+10179 is GREEK YEAR SIGN, props \pS \p{So}
# code point U+110BD is KAITHI NUMBER SIGN, props \pC \p{Cf}
"\x{10179}$sample\x{2013}\x{110BD}$sample",
);
现在让 $date
成为遍历该数组的 foreach
迭代器,我们得到以下输出:
Original is: 17/01/2010
First method: 2010-01-17
Second method: 2010-01-17
Third method: 2010-01-17
Fourth method: 2010-01-17
Original is: this 17/01/2010 and that 17/01/2010 there
First method: 2010 there-01-2010 and that 17-01-this 17
Second method: this 2010-01-17 and that 2010-01-17 there
Third method: this 2010-01-17 and that 2010-01-17 there
Fourth method: this 2010-01-17 and that 2010-01-17 there
Original is: from “17/01/2010” through 17/01/2010
First method: 2010-01-2010” through 17-01-from “17
Second method: from “2010-01-17” through 2010-01-17
Third method: from “2010-01-17” through 2010-01-17
Fourth method: from “2010-01-17” through 2010-01-17
Original is: 𐅹17/01/2010–17/01/2010
First method: 2010-01-2010–17-01-𐅹17
Second method: 𐅹2010-01-17–2010-01-17
Third method: 𐅹2010-01-17–2010-01-17
Fourth method: 𐅹2010-01-17–2010-01-17
现在假设您确实想要匹配非 ASCII 数字。例如:
U+660 ARABIC-INDIC DIGIT ZERO
U+661 ARABIC-INDIC DIGIT ONE
U+662 ARABIC-INDIC DIGIT TWO
U+663 ARABIC-INDIC DIGIT THREE
U+664 ARABIC-INDIC DIGIT FOUR
U+665 ARABIC-INDIC DIGIT FIVE
U+666 ARABIC-INDIC DIGIT SIX
U+667 ARABIC-INDIC DIGIT SEVEN
U+668 ARABIC-INDIC DIGIT EIGHT
U+669 ARABIC-INDIC DIGIT NINE
甚至
U+1D7F6 MATHEMATICAL MONOSPACE DIGIT ZERO
U+1D7F7 MATHEMATICAL MONOSPACE DIGIT ONE
U+1D7F8 MATHEMATICAL MONOSPACE DIGIT TWO
U+1D7F9 MATHEMATICAL MONOSPACE DIGIT THREE
U+1D7FA MATHEMATICAL MONOSPACE DIGIT FOUR
U+1D7FB MATHEMATICAL MONOSPACE DIGIT FIVE
U+1D7FC MATHEMATICAL MONOSPACE DIGIT SIX
U+1D7FD MATHEMATICAL MONOSPACE DIGIT SEVEN
U+1D7FE MATHEMATICAL MONOSPACE DIGIT EIGHT
U+1D7FF MATHEMATICAL MONOSPACE DIGIT NINE
假设您有一个等宽数字的日期,如下所示:
$date = "\x{1D7F7}\x{1D7FD}/\x{1D7F7}\x{1D7F6}/\x{1D7F8}\x{1D7F6}\x{1D7F7}\x{1D7F6}";
Perl 代码可以很好地处理它:
Original is: 𝟷𝟽/𝟷𝟶/𝟸𝟶𝟷𝟶
First method: 𝟸𝟶𝟷𝟶-𝟷𝟶-𝟷𝟽
Second method: 𝟸𝟶𝟷𝟶-𝟷𝟶-𝟷𝟽
Third method: 𝟸𝟶𝟷𝟶-𝟷𝟶-𝟷𝟽
Fourth method: 𝟸𝟶𝟷𝟶-𝟷𝟶-𝟷𝟽
我想你会发现 Python 有一个相当脑残的 Unicode 模型,它缺乏对抽象字符和字符串的支持,不管内容如何,这使得编写这样的东西变得非常困难。
在将子表达式的声明与其执行分离的情况下,在 Python 中编写清晰的正则表达式也很困难,因为那里不支持 (?(DEFINE)...)
block 。见鬼,Python 甚至不支持 Unicode 属性。因此,它不适合 Unicode 正则表达式工作。
但是嘿,如果你认为 Python 与 Perl 相比很糟糕(确实如此),那就试试其他语言吧。对于这类工作,我还没有找到一个不差的。
如您所见,当您请求多种语言的正则表达式解决方案时,您会遇到真正的问题。首先,由于不同的正则表达式风格,解决方案很难进行比较。还因为没有其他语言可以在正则表达式的功能、表达能力和可维护性方面与 Perl 相提并论。一旦出现任意 Unicode,这可能会变得更加明显。
因此,如果您只想要 Python,那么您应该只要求它。否则,这是一场非常不公平的比赛,Python 几乎总是会输;在 Python 中正确处理这样的事情太麻烦了,更不用说都正确和干净了。这要求它比它能产生的更多。
相比之下,Perl 的正则表达式在这两个方面都表现出色。
关于python - Perl 或 Python : Convert date from dd/mm/yyyy to yyyy-mm-dd,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4077896/