我想获取 context.xml 中的 companyName 值
编写下面提到的代码后，我得到了 null 值
请帮助我从 context.xml 获取值。您甚至可以通过其他方式从 context.xml
注意:不要说在 web.xml
Context.xml (Tomcat 7)
<?xml version='1.0' encoding='utf-8'?>
<!--
Licensed to the Apache Software Foundation (ASF) under one or more
contributor license agreements. See the NOTICE file distributed with
this work for additional information regarding copyright ownership.
The ASF licenses this file to You under the Apache License, Version 2.0
(the "License"); you may not use this file except in compliance with
the License. You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
-->
<!-- The contents of this file will be loaded for each web application -->
<Context>
<!-- Default set of monitored resources -->
<WatchedResource>WEB-INF/web.xml</WatchedResource>
<!-- Uncomment this to disable session persistence across Tomcat restarts -->
<!--
<Manager pathname="" />
-->
<!-- Uncomment this to enable Comet connection tacking (provides events
on session expiration as well as webapp lifecycle) -->
<!--
<Valve className="org.apache.catalina.valves.CometConnectionManagerValve" />
-->
<Parameter name="companyName" value="My Company, Incorporated"
override="false"/>
</Context>
JSP(index.jsp)
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<%
ServletContext sc= getServletContext();
String testNameValue = sc.getInitParameter("companyName");
%>
<input type="text" value="<%=testNameValue%>">
</body>
</html>
输出
在实现下面给出的解决方案后更新
出现异常
最佳答案
你不能那样加载因为context.xml是 JNDI 资源。请尝试以下方法:
Tomcat (context.xml)
<Parameter name="companyName" value="My Company, Incorporated" override="false"/>
Java 端
InitialContext context = new InitialContext();
Context xmlNode = (Context) context.lookup("java:comp/env");
String companyName = (String) xmlNode.lookup("companyName");
Spring 侧 家庭 Controller .java
@Controller
@RequestMapping("/")
public class HomeController {
@Autowired
private ServletContext servletContext;
@RequestMapping(method=RequestMethod.GET)
public ModelAndView index(ModelAndView mav) throws Exception {
String companyName = servletContext.getInitParameter("companyName");
mav.setViewName("home/index");
mav.addObject("companyName", companyName);
return mav;
}
public void setServletContext(ServletContext servletContext) {
this.servletContext = servletContext;
}
}
查看侧面 索引.jsp
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Home</title>
</head>
<body>
<c:out value="${companyName}"/>
</body>
</html>
上面的例子在我这边被证明是成功的。我的脚本可以从 context.xml 读取运行时的文件，如图所示。
关于java - 我想读取tomcat context.xml的参数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/41227888/