我正在开发一个 spring mvc 项目，我已经使用 Tomcat FORM 身份验证进行登录。 并且应用程序运行良好，所以现在我正在研究注销实现。 该应用程序的主页 (home.jsp) 带有注销链接，我正在尝试调用一个 LogoutServlet，如下所示。
LogoutServlet.java
@WebServlet(urlPatterns={"/logout"})
public class LogoutServlet extends HttpServlet {
protected void doGet(HttpServletRequest request,HttpServletResponse response)
throws ServletException, IOException {
// To logout the current user
request.getSession().invalidate();
// The user is now logged out so redirect the user to the welcome.jsp page .
response.sendRedirect(request.getContextPath() + "/welcome.jsp");
}
首页.jsp
<body>
<a href="LogoutServlet">Logout</a>
<form:form id="formDataBean" method="post" modelAttribute="formDataBean" action="submit" class="form" >
//form body
.
.
</form:form>
</body>
web.xml
<welcome-file-list>
<welcome-file>welcome.jsp</welcome-file>
</welcome-file-list>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml,classpath*:gameResult-context.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<security-constraint>
<web-resource-collection>
<web-resource-name>Admin</web-resource-name>
<url-pattern>/*</url-pattern>
<http-method>GET</http-method>
<http-method>POST</http-method>
</web-resource-collection>
<auth-constraint>
<role-name>tomcat</role-name>
</auth-constraint>
<user-data-constraint>
<transport-guarantee>NONE</transport-guarantee>
</user-data-constraint>
</security-constraint>
<login-config>
<auth-method>FORM</auth-method>
<form-login-config>
<form-login-page>/login</form-login-page>
<form-error-page>/login-failed</form-error-page>
</form-login-config>
</login-config>
// i have a doubt on the below code as i don't know if it has to be there at all
// because when ever i start the application (server) this servlet gets initialize
// and doGet() gets execute.
<servlet>
<servlet-name>LogoutServlet</servlet-name>
<servlet-class>org.sample.servlets.LogoutServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>LogoutServlet</servlet-name>
<url-pattern>/logout/*</url-pattern>
</servlet-mapping>
</web-app>
这是问题所在:
我想从注销链接调用 LogoutServlet 并重定向到 welcome.jsp 页面，但现在它不工作，它抛出 HTTP 状态 404 错误 (http://localhost:8080/gameResult/LogoutServlet).
最佳答案
根据您的 Servlet，您可能应该改为调用 http://localhost:8080/gameResult/logout。
<a href="logout">Logout</a>
如果您在另一个路径中使用此代码，您可以自动添加上下文以消除进一步的问题，这样您就不必担心相对路径。
<a href="${pageContext.request.contextPath}/logout">Logout</a>
此外，您应该从 web.xml 中删除这些内容:
<servlet>
<servlet-name>LogoutServlet</servlet-name>
<servlet-class>org.sample.servlets.LogoutServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>LogoutServlet</servlet-name>
<url-pattern>/logout/*</url-pattern>
</servlet-mapping>
因为你使用的是WebServlet注解。
关于jsp - 从 jsp <href> 链接调用 Servlet 无效，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/20920632/