当我尝试加载 http://localhost:8080/people
时,我收到 404 页面未找到错误。
这是我在 web.xml 中的 servlet 映射:
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:applicationContext.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/people/*</url-pattern>
</servlet-mapping>
我的理解是这样的:
对 http://localhost:8080/people
的 url 请求将被 servlet“spring”拦截并调用类 org.springframework.web.servlet.DispatcherServlet
这是正确的吗?
我是否需要一些额外的配置才能正确加载此类?
更新:
这是 Controller :
@Controller
public class PersonController {
@Autowired
private PersonService personService;
@RequestMapping("/")
public String listPeople(Map<String, Object> map) {
map.put("person", new Person());
map.put("peopleList", personService.listPeople());
return "people";
}
@RequestMapping(value = "/add", method = RequestMethod.POST)
public String addPerson(@ModelAttribute("person") Person person, BindingResult result) {
personService.addPerson(person);
return "redirect:/people/";
}
@RequestMapping("/delete/{personId}")
public String deletePerson(@PathVariable("personId") Integer personId) {
personService.removePerson(personId);
return "redirect:/people/";
}
}
最佳答案
你有 controller
来支持你的 GET
响应吗?
像这样
@Controller
@RequestMapping(value = "/people")
public class LoginController {
@RequestMapping(value = "/i_am_here", method = RequestMethod.GET)
public String firstForm() {
return "SHOW_ME_THE_JSP_PAGE";
}
}
基于上面的示例,这将使您的获取 URL 请求类似于 ->/people/i_am_here
方法将被调用,响应可以在 JSP
中发回。
Checkout this example under Github
https://github.com/hth/StatusInvoke/blob/master/src/com/example/UserController.java
关于Spring servlet 映射不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19213779/