tomcat - java.lang.IllegalArgumentException : Invalid <url-pattern> in servlet mapping 异常

Question

<servlet>
    <servlet-name>myservlet</servlet-name>
    <servlet-class>workflow.WDispatcher</servlet-class>
    <load-on-startup>2</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>myservlet</servlet-name>
    <url-pattern>*NEXTEVENT*</url-pattern>
</servlet-mapping>

以上是 Tomcat 的 web.xml 的片段。 URL 模式 *NEXTEVENT* 在启动时抛出

java.lang.IllegalArgumentException: Invalid <url-pattern> in servlet mapping

如果有人能指出错误，将不胜感激。

Answer 1

<url-pattern>*NEXTEVENT*</url-pattern>

URL 模式无效。它可以以星号结尾或以星号开头(表示文件扩展名映射)。

url-pattern 规范:

• A string beginning with a ‘/’ character and ending with a ‘/*’ suffix is used for path mapping.
• A string beginning with a ‘*.’ prefix is used as an extension mapping.
• A string containing only the ’/’ character indicates the "default" servlet of the application. In this case the servlet path is the request URI minus the context path and the path info is null.
• All other strings are used for exact matches only.

参见 Java Servlet Specification 的第 12.2 节3.1 版了解更多详情。