我尝试使用以下代码在具有日期时间 x 轴的图形上绘制一个矩形:
from datetime import datetime, timedelta
from matplotlib.patches import Rectangle
import matplotlib.pyplot as plt
# Create new plot
fig = plt.figure()
ax = fig.add_subplot(111)
# Create rectangle
startTime = datetime.now()
width = timedelta(seconds = 1)
endTime = startTime + width
rect = Rectangle((startTime, 0), width, 1, color='yellow')
# Plot rectangle
ax.add_patch(rect) ### ERROR HERE!!! ###
plt.xlim([startTime, endTime])
plt.ylim([0, 1])
plt.show()
但是,我得到了错误:
TypeError: unsupported operand type(s) for +: 'float' and 'datetime.timedelta'
怎么了? (我使用的是 matplotlib 版本 1.0.1)
最佳答案
问题是 matplotlib 使用它自己的日期/时间表示( float 天数),因此您必须先转换它们。此外,您必须告诉 xaxis 它应该有日期/时间刻度和标签。下面的代码就是这样做的:
from datetime import datetime, timedelta
from matplotlib.patches import Rectangle
import matplotlib.pyplot as plt
import matplotlib.dates as mdates
# Create new plot
fig = plt.figure()
ax = fig.add_subplot(111)
# Create rectangle x coordinates
startTime = datetime.now()
endTime = startTime + timedelta(seconds = 1)
# convert to matplotlib date representation
start = mdates.date2num(startTime)
end = mdates.date2num(endTime)
width = end - start
# Plot rectangle
rect = Rectangle((start, 0), width, 1, color='yellow')
ax.add_patch(rect)
# assign date locator / formatter to the x-axis to get proper labels
locator = mdates.AutoDateLocator(minticks=3)
formatter = mdates.AutoDateFormatter(locator)
ax.xaxis.set_major_locator(locator)
ax.xaxis.set_major_formatter(formatter)
# set the limits
plt.xlim([start-width, end+width])
plt.ylim([-.5, 1.5])
# go
plt.show()
结果:
注意:Matplotlib 1.0.1 非常旧。我不能保证我的例子会起作用。你应该尝试更新!
关于python - 如何使用 matplotlib 在日期时间轴上绘制矩形?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31162780/