我在 Angular 7 中有一个简单的应用程序,它使用 giphy api 发出 gif 列表请求,通知 gif 的数量和搜索词。
我想创建一个发出请求的测试,并验证 gif 列表的结果是否大于 0。
但是我有很多错误而且我不明白为什么
服务
private apiKey:string = "123";
private shortUrl:string = "//api.giphy.com/v1/gifs/search?q="
searchGif(term:string, limit:number):Observable<Gif[]> {
let url:string = this.getUrl(term, limit);
return this.http.get<Gif[]>(`${url}/`);
}
测试
let service: GifSearchService;
let httpMock: any
let limit: number = 1;
let term: string = "dogs";
beforeEach(() => {
httpMock = jasmine.createSpyObj('http', [ 'get', 'post' ]);
service = new GifSearchService(httpMock);
});
it('Should return value when search for gifs', () => {
let result = service.searchGif(term, limit);
expect(result.length).toBeGreaterThan(0);
});
错误
ERROR in node_modules/rxjs/internal/Observable.d.ts(14,60): error TS1183: An implementation cannot be declared in ambient contexts. src/app/gif-list/gif-list.component.spec.ts(33,19): error TS2339: Property 'length' does not exist on type 'Observable'.
最佳答案
我认为唯一有意义的测试是测试它是否返回一个 Observable...就像这样..
expect(results).toEqual(jasmine.any(Observable))
关于javascript - Jasmine 的错误方法http测试( Angular 7),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56261910/