c# - 使用 Newtonsoft.Json 反序列化

Question

我是一名测试人员，正在学习 C# 和 REST 服务测试，这对我来说都是新的…… 我有一个像这样的 JSON 响应

{ "results" : [
    {
        "address_components" : [
        {
            "long_name" : "1600",
            "short_name" : "1600",
            "types" : [ "street_number" ]
        },
        {
            "long_name" : "Amphitheatre Parkway",
            "short_name" : "Amphitheatre Pkwy",
            "types" : [ "route" ]
        },
        {
            "long_name" : "Mountain View",
            "short_name" : "Mountain View",
            "types" : [ "locality", "political" ]
        },
        {
            "long_name" : "Santa Clara County",
            "short_name" : "Santa Clara County",
            "types" : [ "administrative_area_level_2", "political" ]
        },
        {
            "long_name" : "California",
            "short_name" : "CA",
            "types" : [ "administrative_area_level_1", "political" ]
        },
        {
            "long_name" : "United States",
            "short_name" : "US",
            "types" : [ "country", "political" ]
        },
        {
            "long_name" : "94043",
            "short_name" : "94043",
            "types" : [ "postal_code" ]
        }
     ],
     "formatted_address" : "1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA",
     "geometry" : {
        "location" : {
           "lat" : 37.4223434,
           "lng" : -122.0843689
        },
        "location_type" : "ROOFTOP",
        "viewport" : {
           "northeast" : {
              "lat" : 37.42369238029149,
              "lng" : -122.0830199197085
           },
           "southwest" : {
              "lat" : 37.42099441970849,
              "lng" : -122.0857178802915
           }
        }
     },
     "place_id" : "ChIJ2eUgeAK6j4ARbn5u_wAGqWA",
     "types" : [ "street_address" ]
  }
],
"status" : "OK"
} 

并将其反序列化为对象，只需要几何/位置中的“lat”和“lng”

我的代码看起来像

JObject myMap = JObject.Parse(response.Content);
IList<JToken> mylist = myMap["results"][0]["geometry"].Children().ToList();`

 IList<location> spots = new List<location>();
foreach (JToken spot in mylist)
{
    Console.WriteLine("\nthe spots are :\t:"+ spot.ToString());
    location somesopt = JsonConvert.DeserializeObject<location>(spot.ToString());
    Console.WriteLine("\n the lat is :\t" + somesopt.lat.ToString());
    Console.WriteLine("\n the lat is :\t" + somesopt.lng.ToString());
}

我的对象是…………

   public class location
{
    public double lat { get; set; }
    public double lng { get; set; }
}

public class geopost
{
    public location geometry;
}

问题是我总是在 json deseserializobject 处得到 JsonSerializationException 我尝试更改定义 mylist 的许多排列 但无法写入....我做错了什么..？

当在地址组件中对“Long_name”和“short_name”使用相同的代码结构时，它工作正常。我知道地址组件是数组，几何/位置是对象。但你如何处理它？<​​/p>

Answer 1

我按照 DavidG 的建议做同样的事情，但我通过将 JSON 复制到剪贴板然后在 VS 上转到菜单 Edit->Paste Special->将 JSON 作为类粘贴。

生成反序列化所需的类:

public class Rootobject
{
    public Result[] results { get; set; }
    public string status { get; set; }
}

public class Result
{
    public Address_Components[] address_components { get; set; }
    public string formatted_address { get; set; }
    public Geometry geometry { get; set; }
    public string place_id { get; set; }
    public string[] types { get; set; }
}

(...)

同样的反序列化方法:

var data = JsonConvert.DeserializeObject<RootObject>(json);