我有一个对数组进行排序的方法,我想测试它,我想将它的结果与预期的结果进行比较,当然我可以使用 for 循环来完成,但我想问是否有是一个 Hamcrest 匹配器来做比较
我有课
class Person{
String name;
int age;
double budget;
Person(String name,int age,double budget){
this.name = name;
this.age = age;
this.budget = budget;
}
@Override
public boolean equals(Object obj) {
if (obj == null || !(obj instanceof Person)) return false;
Person p = (Person) obj;
if (((Person) obj).budget == budget && ((Person) obj).age == age && ((Person) obj).name.equals(name)) {
return true;
}
return false;
}
}
我的测试方法是这样的
@Test
public void InsertionSortOfObjectUsingComparator() {
Person p1 = new Person("A", 18, 800);
Person p2 = new Person("K", 15, 1800);
Person p3 = new Person("L", 18, 600);
Person[] persons = {p1,p2,p3};
Person[] expected = {p3, p1, p2};
Person[] result = (new Sort()).sort(persons, Comparator.<Person>comparingDouble(o-> o.budget);
//want to compare the content of the two arrays result and expected; using assertThat
}
是否可以使用 Hamcrest 来实现?如果是,怎么办?
更新
是的,这是可能的,使用 IsArrayContainingInOrder.arrayContaining
....
assertThat(expected, IsArrayContainingInOrder.arrayContaining((new InsertionSort().sort(persons, Comparator.comparingDouble(o -> o.budget)))));
assertThat(3,is((new InsertionSort().sort(persons, Comparator.comparingDouble(o -> o.budget))).length));
}
最佳答案
数组可以用最简单的is
匹配器来匹配,例如:
import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.core.Is.is;
// ...
assertThat(result, is(new byte[]{1, 2, 3}));
在底层,它会发现输入是一个数组。它将为数组使用适当的匹配器(即不仅仅是 a.equal(b)
)。
关于java - Hamcrest 匹配器比较两个数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54439629/