经过几个小时的谷歌搜索和测试,我似乎应该能够找到这个问题的明显答案。
我希望能够在 caredate 工厂中设置 caredate.user_id => provider.user_id。
测试错误:
ActiveRecord::RecordInvalid: Validation failed: User must be same as provider user
我有一个 ActiveRecord 验证,它在通过浏览器测试时有效:
class Caredate < ActiveRecord::Base //works fine when testing via browser
belongs_to :user
belongs_to :provider
validates_presence_of :user_id
validates_presence_of :provider_id
validate :user_must_be_same_as_provider_user
def user_must_be_same_as_provider_user
errors.add(:user_id, "must be same as provider user") unless self.user_id == self.provider.user_id
end
end
//factories.rb
Factory.define :user do |f|
f.password "test1234"
f.sequence(:email) { |n| "foo#{n}@example.com" }
end
Factory.define :caredate do |f|
f.association :provider
**f.user_id { Provider.find_by_id(provider_id).user_id } //FAILS HERE**
end
Factory.define :provider do |f|
f.association :user
end
如果之前已经回答过这个问题,我深表歉意;我尝试了几种不同的选择,但无法正常工作。
更新:这通过了验证,所以我离它越来越近了。我可以破解一个随机数。
Factory.define :caredate do |f|
f.association :user, :id => 779
f.association :provider, :user_id => 779
end
最佳答案
Factory.define :caredate do |f|
provider = Factory.create(:provider)
f.provider provider
f.user provider.user
end
关于ruby-on-rails - 工厂女工的依赖属性,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4410854/