在下面的代码中,我有一个构建衬衫的页面。当用户单击一个选项(“男/女”)时,“#shirt”部分显示通过将 PNG 图像叠加在一起构建的衬衫。例如,选择“蓝色”作为基色将显示蓝色衬衫的图像。然后,选择“罗纹” body 拼接将在蓝色衬衫顶部放置一个图像,添加罗纹细节。现在,我的问题是每个新图像都会替换以前的图像。其他一切正常(选项出现以响应先前选择的选项)。
<div id="gender" class="diy-box">
Pick Gender<br>
<input type="radio" name="gender" data-id="" value="male" /><label>Male</label><br>
<input type="radio" name="gender" data-id="" value="female" /><label>Female</label>
</div>
<section id="displaysection">
<div id="male" class="desc gender diy-box">
Pick Body<br>
<input type="radio" name="male" data-id="105" value="" /><label>Blue</label><br>
<input type="radio" name="male" data-id="120" value="" /><label>Black</label><br>
<input type="radio" name="male" data-id="145" value="" /><label>White</label>
</div>
<div id="female" class="desc gender diy-box">
Pick Body<br>
<input type="radio" name="female" data-id="107" value="" /><label>Blue</label><br>
<input type="radio" name="female" data-id="211" value="" /><label>Black</label><br>
<input type="radio" name="female" data-id="212" value="" /><label>Pink</label>
</div>
</section>
<div id="body_stitching" class="diy-box">
Body Stitching<br>
<input type="radio" name="body_stitching" data-id="" value="body_stitching_plain" /><label>Plain</label><br>
<input type="radio" name="body_stitching" data-id="" value="body_stitching_rib" /><label>Rib</label>
</div>
<section id="displaysection">
<div id="body_stitching_plain" class="desc body_stitching diy-box">
Plain<br>
<input type="radio" name="body_stitching_plain" data-id="324" value="" /><label>Blue</label><br>
<input type="radio" name="body_stitching_plain" data-id="325" value="" /><label>Red</label>
</div>
<div id="body_stitching_rib" class="desc body_stitching diy-box">
Rib<br>
<input type="radio" name="body_stitching_rib" data-id="" value="black" /><label>Black</label><br>
<input type="radio" name="body_stitching_rib" data-id="" value="green" /><label>Green</label>
</div>
</section>
<div class="clear"></div>
<div id="shirt"></div>
<div id="pricefield" style="float:right"></div>
<script>
$(document).ready(function() {
$("div.desc").hide();
var data = {
"105" : { img: "http://oceandrive.localhost/images/diy-images/105.png", label: "color 1", price: "100" },
"120" : { img: "http://oceandrive.localhost/images/diy-images/120.png", label: "color 2", price: "110" },
"145" : { img: "http://oceandrive.localhost/images/diy-images/145.png", label: "color 3", price: "120" },
"107" : { img: "http://oceandrive.localhost/images/diy-images/107.gif", label: "color 4", price: "130" },
"211" : { img: "http://oceandrive.localhost/images/diy-images/211.png", label: "color 5", price: "140" },
"212" : { img: "http://oceandrive.localhost/images/diy-images/212.png", label: "color 6", price: "150" },
"324" : { img: "http://oceandrive.localhost/images/diy-images/324.png", label: "color 7", price: "160" },
"325" : { img: "http://oceandrive.localhost/images/diy-images/325.png", label: "color 8", price: "170" },
};
$('input[name]').click(function() {
var value = $(this).val(); // pics the value of the radio button
if(value=='male' || value=='female') {
$("div.gender").hide('slow');
$("div.gender input:radio").removeAttr('checked');
}
if(value=='body_stitching_plain' || value=='body_stitching_rib') {
$("div.body_stitching").hide('slow');
$("div.body_stitching input:radio").removeAttr('checked');
}
$("#" + value).show('slow'); // addresses the div with the radio button value picked
if(this.checked) {
//var value = $(this).val();
var value = $(this).data('id');
if (data[value] != undefined)
{
var html = '';
html = html + '<img style="z-index:2;" src="'+data[value].img+'"/>';
$('#shirt').html(html);
var html = '';
html = html + '- '+data[value].label+' - '+data[value].price+' NT<br>';
$('#pricefield').html(html);
}
}
});
});
最佳答案
首先,您需要确定图像的显示顺序。例如,根据您的代码,我会说您有两个级别(如果需要,您可以添加更多级别):
- 基地
- body 拼接
其次,将每个级别分配给一个 z-index 并创建 <div>
每个元素。这些<div>
的样式应使其定位是绝对的,如下所示:
<div id="baseImage" style="z-index:1; position: absolute;"></div>
<div id="stitchImage" style="z-index:2; position: absolute;"></div>
...
我可能还会指定每个 <div>
的宽度/高度以匹配您的图像。
最后,使用 jQuery 定位每个 <div>
在基本图像之上。
$("#stitchImage").offset($("#baseImage").offset());
然后,当您需要替换图像时,只需使用您拥有的代码即可:
$("#stitchImage").html("<img src='" + src + "' />");
请注意,您必须使用空白占位图像,以便用户在尚未选择较高层时可以看到较低层。
关于Jquery:如何将图像叠加在一起?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10817644/