我正在尝试在 Canvas 上找到红色,例如,假设我在 Canvas 上画了一个正方形,所以我想知道如何循环遍历该正方形,当我检测到它时得到 x从现在开始我有这个:
var imgData = context.getImageData(face.x-1, face.y-1, 15+2, 15+2);
var pixels = imgData.data;
for (var i = 0; n = pixels.length, i < n; i += 4) {
var red = pixels[i];
var green = pixels[i+1];
var blue = pixels[i+2];
var alpha = pixels[i+3];
//red color
if(red == 255 && green == 0 && blue == 0){
//fired when color is red
}
注意:face.x和face.y是定位图像的X和Y
如何循环正方形,假设它是全黑的,但有 5 个像素是红色的,我想检测它在哪里,并从 Canvas 中的图像中获取 X 和 Y
这是我的Jsfiddle (我试图在 Canvas 上找到红色,例如,假设我在 Canvas 上画了一个正方形,所以我想知道如何循环遍历该正方形,当我检测到它时得到 x 和 y从现在开始我有这个:
var imgData = context.getImageData(face.x-1, face.y-1, 15+2, 15+2);
var pixels = imgData.data;
for (var i = 0; n = pixels.length, i < n; i += 4) {
var red = pixels[i];
var green = pixels[i+1];
var blue = pixels[i+2];
var alpha = pixels[i+3];
//red color
if(red == 255 && green == 0 && blue == 0){
//fired when color is red
}
注意:face.x和face.y是定位图像的X和Y
如何循环正方形,假设它是全黑的,但有 5 个像素是红色的,我想检测它在哪里,并从 Canvas 中的图像中获取 X 和 Y
我把这个放了
img.src = "https://i.imgur.com/x9uJH7a.gif";
imgCara.src = "https://i.imgur.com/vJJlYw2.png";
但这只是一个测试,向您展示我正在尝试做什么(这些 img 是我在我的元素中使用的),但我在 jsfiddle 上看不到它......
我尝试用
定位var w = cara.x-1 + ((i / 4) % (imgData.width));
var z = cara.y-1 + Math.floor((i /4)/(imgData.width));
但是不起作用。
编辑
我遇到了这个问题...
我创建它是为了保存 x 和 y:
var xy={x:2,y:2};
然后我调整了你的循环:
function findMatchingXY(R,G,B,tolerance){
// get the pixel data of the canvas
var data=context.getImageData(0,0,img.width,img.height).data;
// loop through all pixels
for(var y=0;y<img.width;y++){
for(var x=0;x<img.height;x++){
// find the pixel data from the data[] rgba array
// representing the pixel at [x,y]
var n=(y*img.width+x)*4;
// compare this pixel's color channels with the targets
var matchesRedTarget=Math.abs(R-data[n])<tolerance;
var matchesGreenTarget=Math.abs(G-data[n+1])<tolerance;
var matchesBlueTarget=Math.abs(B-data[n+2])<tolerance;
// does this pixel match the target
if(data[n+3]>30 && matchesRedTarget
&& matchesGreenTarget && matchesBlueTarget){
// return the x,y of the first matching pixel
return({x:x,y:y});
}
}}
// no matching pixels found, return null
return(null);
}
在 Chrome 中它说:
maze.js:26 Uncaught TypeError: Cannot read property 'x' of null
最佳答案
由于我只有 51% 确定我理解您的问题,因此我将保留此示例代码,希望它可以帮助您回答或澄清您的问题。代码的关键部分是 findMatchingXY
函数——我对其进行了注释以展示其工作原理。
var canvas=document.getElementById("canvas");
var ctx=canvas.getContext("2d");
var cw=canvas.width;
var ch=canvas.height;
var size=15;
var $xy=$('#xy');
var targetRed=255;
var targetGreen=255;
var targetBlue=187;
var tolerance=5;
ctx.fillStyle='black';
ctx.fillRect(0,0,cw,ch);
$('#place').on('click',function(){
// calc a random x,y and draw a 15x15 rect there
var x=Math.random()*(cw-size);
var y=Math.random()*(ch-size);
ctx.fillStyle='black';
ctx.fillRect(0,0,cw,ch);
ctx.fillStyle='rgb('+targetRed+','+targetGreen+','+targetBlue+')';
ctx.fillRect(x,y,15,15);
});
$('#find').on('click',function(){
var xy=findMatchingXY();
if(xy){
$xy.text('Found the matching rect at x='+xy.x+', y='+xy.y);
}else{
$xy.text('There is no matching rect');
}
});
$('#place').trigger('click');
function findMatchingXY(){
// get the pixel data of the canvas
var data=ctx.getImageData(0,0,cw,ch).data;
// loop through all pixels
for(var y=0;y<ch;y++){
for(var x=0;x<cw;x++){
// find the pixel data from the data[] rgba array
// representing the pixel at [x,y]
var n=(y*cw+x)*4;
// compare this pixel's color channels with the targets
var matchesRedTarget=Math.abs(targetRed-data[n])<tolerance;
var matchesGreenTarget=Math.abs(targetGreen-data[n+1])<tolerance;
var matchesBlueTarget=Math.abs(targetBlue-data[n+2])<tolerance;
// does this pixel match the target
if(data[n+3]>30 && matchesRedTarget
&& matchesGreenTarget && matchesBlueTarget){
// return the x,y of the first matching pixel
return({x:x,y:y});
}
}}
// no matching pixels found, return null
return(null);
}
body{ background-color: ivory; }
#canvas{border:1px solid red; margin:0
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<button id='place'>Randomly place a rect</button>
<button id='find'>Find the randomly placed rect</button><br>
<h4 id='xy'>Place a target-color rect then find it.</h4>
<canvas id="canvas" width=300 height=100></canvas>
[添加:使用迷宫图像的示例]
var canvas=document.getElementById("canvas");
var ctx=canvas.getContext("2d");
var cw=canvas.width;
var ch=canvas.height;
var $xy=$('#xy');
var img=new Image();
img.crossOrigin='anonymous';
img.onload=start;
img.src="https://dl.dropboxusercontent.com/u/139992952/multple/mazeRed.png";
function start(){
cw=canvas.width=img.width;
ch=canvas.height=img.height;
ctx.drawImage(img,0,0);
var xy=findMatchingXY(255,47,47,10);
if(xy){
$xy.text('Found the matching pixel at x='+xy.x+', y='+xy.y);
}else{
$xy.text('There is no matching pixel');
}
}
function findMatchingXY(targetRed,targetGreen,targetBlue,tolerance){
// get the pixel data of the canvas
var data=ctx.getImageData(0,0,cw,ch).data;
// loop through all pixels
for(var y=0;y<ch;y++){
for(var x=0;x<cw;x++){
// find the pixel data from the data[] rgba array
// representing the pixel at [x,y]
var n=(y*cw+x)*4;
// compare this pixel's color channels with the targets
var matchesRedTarget=Math.abs(targetRed-data[n])<tolerance;
var matchesGreenTarget=Math.abs(targetGreen-data[n+1])<tolerance;
var matchesBlueTarget=Math.abs(targetBlue-data[n+2])<tolerance;
// does this pixel match the target
if(data[n+3]>30 && matchesRedTarget
&& matchesGreenTarget && matchesBlueTarget){
// return the x,y of the first matching pixel
return({x:x,y:y});
}
}}
// no matching pixels found, return null
return(null);
}
body{ background-color: ivory; }
#canvas{border:1px solid red; margin:0 auto; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<h4 id='xy'>Finding red line in maze</h4><br>
<canvas id="canvas" width=300 height=100></canvas>
关于javascript - 循环直到在 Canvas 中找到一些具有相同颜色的像素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37030308/