我有这个切换按钮代码。如何通过 POST 方法从此切换按钮传递值..
<div class="form-group col-md-4">
<label>Sold Out</label>
<div>
<button data-toggle="collapse">YES</button>
<button data-toggle="collapse">NO</button>
</div>
</div>
最佳答案
试试这个
<?php
if (isset($_POST['yesBtn'])) {
echo "<p>".$_POST['yesBtn']."</p>";
}
if (isset($_POST['noBtn'])) {
echo "<p>".$_POST['noBtn']."</p>";
}
?>
<form action="somefile.php" method="POST">
<div class="form-group col-md-4">
<label>Sold Out</label>
<div>
<button data-toggle="collapse" name="yesBtn" value="YES">YES </button>
<button data-toggle="collapse" name="noBtn" value="NO">NO</button>
</div>
</div>
</form>
或者这个
<?php
if (isset($_POST['Btn'])) {
echo "<p>".$_POST['Btn']."</p>";
}
?>
<form action="somefile.php" method="POST">
<div class="form-group col-md-4">
<label>Sold Out</label>
<div>
<button data-toggle="collapse" name="btn" value="YES">YES </button>
<button data-toggle="collapse" name="btn" value="NO">NO</button>
</div>
</div>
</form>
关于jquery - 如何在 Bootstrap 的切换按钮中传递值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42548136/