我使用 dataTable 插件来格式化我的 html 表格。但它没有显示我想要的结果。它显示所有记录而不是每页 10 条记录。我也使用 iDisplayLength: 10 但它不起作用。
我的代码:-
<html>
<head>
<script src="https://code.jquery.com/jquery-1.11.1.min.js"></script>
<script src="https://cdn.datatables.net/1.10.4/js/jquery.dataTables.min.js"></script>
<script>
$(document).ready(function(){
$('#count').DataTable({
"pagingType": "full_numbers",
"iDisplayLength": 10
}
);
});
</script>
<link rel="stylesheet" href="https://cdn.datatables.net/1.10.4/css/jquery.dataTables.min.css">
</head>
<table id="count">
<thead>
<tr>
<th>Quarter ID</th>
<th>Locality Name</th>
<th>Block</th>
<th>Floor</th>
<th>RB Type</th>
<th>Quarter Type</th>
<th>Quarter No</th>
<th>No of Rooms</th>
<th>Servant quarter</th>
<th>Status</th>
</tr>
</thead>
<?php
require 'connection.php';
$q8="select * from mstquarters";
$q9=mysqli_query($con,$q8);
if(mysqli_num_rows($q9)>=1)
{
while($row=mysqli_fetch_array($q9))
{
?>
<?php
$y=$row['blockId'];
$q5="select * from mstblocks where blockId='$y'";
$r5=mysqli_query($con,$q5);
$r6=mysqli_fetch_array($r5);
$r7=$r6['block'];
$z=$row['localityId'];
$q6="select * from mstlocalities where localityId='$z'";
$s5=mysqli_query($con,$q6);
$s6=mysqli_fetch_array($s5);
$s7=$s6['localitySName'];
?>
<tbody>
<tr>
<td><?php echo $row['quarterId'];?></td>
<td><?php echo $s7;?></td>
<td><?php echo $r7;?></td>
<td><?php echo $row['floor'];?></td>
<td><?php echo $row['rbType'];?></td>
<td><?php echo $row['quarterType'];?></td>
<td><?php echo $row['quarterNo'];?></td>
<td><?php echo $row['noOfRooms'];?></td>
<td><?php echo $row['servantQuarter'];?></td>
<td><?php echo $row['status'];?></td>
</tr>
</tbody>
<?php
}
}
?>
</table>
</html>
我已经包含了 javascript 文件，我是否应该包含更多文件才能正常工作？
最佳答案
问题是您正在创建 <tbody>里面while()这创建了错误的表结构。
放在while()之外你会很高兴去
像这样:-
</thead>
<tbody>
<?php
require 'connection.php';
$q8="select * from mstquarters";
$q9=mysqli_query($con,$q8);
if(mysqli_num_rows($q9)>=1)
{
while($row=mysqli_fetch_array($q9))
{
?>
<?php
$y=$row['blockId'];
$q5="select * from mstblocks where blockId='$y'";
$r5=mysqli_query($con,$q5);
$r6=mysqli_fetch_array($r5);
$r7=$r6['block'];
$z=$row['localityId'];
$q6="select * from mstlocalities where localityId='$z'";
$s5=mysqli_query($con,$q6);
$s6=mysqli_fetch_array($s5);
$s7=$s6['localitySName'];
?>
<tr>
<td><?php echo $row['quarterId'];?></td>
<td><?php echo $s7;?></td>
<td><?php echo $r7;?></td>
<td><?php echo $row['floor'];?></td>
<td><?php echo $row['rbType'];?></td>
<td><?php echo $row['quarterType'];?></td>
<td><?php echo $row['quarterNo'];?></td>
<td><?php echo $row['noOfRooms'];?></td>
<td><?php echo $row['servantQuarter'];?></td>
<td><?php echo $row['status'];?></td>
</tr>
<?php
}
}
?>
</tbody>
</table>
关于javascript - dataTable 插件不工作，它在一页中显示所有记录，我每页只需要 10 条记录，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/47195254/