我有四个 div，每个 div 包含图像和内容。一个下一个和上一个按钮。一次只有 div 会显示。单击下一步，必须显示第二个 div，第一个将隐藏。相同的第四个分区。需要使用纯 Javascript。 不允许使用 jquery 或 javascript 插件.... :(。任何人都可以帮我做这个吗？
谢谢!
我的 html 代码:
<html >
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<div id="container">
<div id="theProduct">
<div id="slides"> <a href="#" class="prev"><img src="img/prev.jpg" width="29" height="29" alt="Arrow Prev"></a> <a href="#" class="next"><img src="img/next.jpg" width="29" height="29" alt="Arrow Next"></a>
<!-- Show/hide Div strating here -->
<div class="slides_container">
<div class="div1">
<div class="img1">
<div class="price">
<ul>
<li class="strike">Rs. 1300</li>
<li class="offer">Rs. 1050</li>
</ul>
<div class="buy"><a href="#">Buy Now</a></div>
</div>
</div>
</div>
<div class="div2">
<div class="img2">
<div class="price">
<ul>
<li class="strike">Rs. 1300</li>
<li class="offer">Rs. 1050</li>
</ul>
<div class="buy"><a href="#">Buy Now</a></div>
</div>
</div>
</div>
<div class="div3">
<div class="img3">
<div class="price">
<ul>
<li class="strike">Rs. 1300</li>
<li class="offer">Rs. 1050</li>
</ul>
<div class="buy"><a href="#">Buy Now</a></div>
</div>
</div>
</div>
<div class="div4">
<div class="img4">
<div class="price">
<ul>
<li class="strike">Rs. 1300</li>
<li class="offer">Rs. 1050</li>
</ul>
<div class="buy"><a href="#">Buy Now</a></div>
</div>
</div>
</div>
</div>
<!-- Show/Hide Div ending here -->
</div>
<img src="img/example-frame.png" width="739" height="341" alt="Example Frame" id="frame"> </div>
</div>
</body>
</html>
最佳答案
下面这个实用
<style type="text/css" media="screen">
#container{position:relative;width:120px;height:120px;}
#container div{position:absolute;width:120px;height:120px;}
#box-red{background:red;}
#box-yellow{background:yellow;display:none;}
#box-green{background:green;display:none;}
#box-maroon{background:maroon;display:none;}
</style>
Javascipt
<script type="text/javascript">
var $c =0;
function next(){
var boxes = document.getElementsByClassName("box");
$c +=1;
if($c >= boxes.length) $c = 0;
for (var $i=0;$i<boxes.length;$i++){
boxes[$i].style.display = "none";
}
boxes[$c].style.display = "block";
return false;
}
function prev(){
var boxes = document.getElementsByClassName("box");
$c -=1;
if($c < 0) $c = (boxes.length-1);
for (var $i=0;$i<boxes.length;$i++){
boxes[$i].style.display = "none";
}
boxes[$c].style.display = "block";
return false;
}
</script>
HTML
<div id="container">
<div id="box-red" class="box">DIV1</div>
<div id="box-yellow" class="box">DIV2</div>
<div id="box-green" class="box">DIV3</div>
<div id="box-maroon" class="box">DIV4</div>
</div>
<a href="#" onClick="return prev();">previous</a> <a href="#" onClick="return next();">next</a>
关于javascript - 使用 Javascript 显示和隐藏带有下一个上一个按钮的图像，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/12930284/