我有一个图 G,其节点和边的属性为“state”。我想绘制图形,标记所有节点,并在相应的边/节点之外标记状态。
for v in G.nodes():
G.node[v]['state']='X'
G.node[1]['state']='Y'
G.node[2]['state']='Y'
for n in G.edges_iter():
G.edge[n[0]][n[1]]['state']='X'
G.edge[2][3]['state']='Y'
命令 draw.networkx 有一个标签选项,但我不明白如何将属性作为标签提供给该命令。有人可以帮帮我吗?
最佳答案
它不是很漂亮 - 但它是这样工作的:
from matplotlib import pyplot as plt
import networkx as nx
G = nx.Graph()
G.add_edge(1,2)
G.add_edge(2,3)
for v in G.nodes():
G.node[v]['state']='X'
G.node[1]['state']='Y'
G.node[2]['state']='Y'
for n in G.edges_iter():
G.edge[n[0]][n[1]]['state']='X'
G.edge[2][3]['state']='Y'
pos = nx.spring_layout(G)
nx.draw(G, pos)
node_labels = nx.get_node_attributes(G,'state')
nx.draw_networkx_labels(G, pos, labels = node_labels)
edge_labels = nx.get_edge_attributes(G,'state')
nx.draw_networkx_edge_labels(G, pos, labels = edge_labels)
plt.savefig('this.png')
plt.show()
关于python - Networkx:如何在图形绘图中显示节点和边属性,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20381460/