css - 以递增的量旋转元素

Question

我有任意数量的 <div>元素。我想要每个 <div>旋转，但增加 2 度。应该怎么做？我不确定仅在 CSS 中是否可行，

例如:

div:nth-child(1) {
  rotate(0deg);
}
div:nth-child(2) {
  transform: rotate(2deg);
}
div:nth-child(3) {
  transform: rotate(4deg);
}

...
// Here is the general equation, but I can't use it in CSS.
div:nth-child(n) {
  transform: rotate( 2*n );
}

Answer 1

试试这个:

$qty: 40;//number of childs
$step:  $qty *2 ;

@for $i from 0 through $qty - 1 {
div:nth-child(#{$i + 1}) {
    transform: rotate( $step+deg) ;
  }
}

also check this