css - 选择第 n 个元素，除非元素位于特定位置并且是 CSS 的最后一个子元素

Question

我想用一个选择器选择所有元素，从第 4 个开始。但我不想选择第 4 个元素，如果它是最后一个元素。

.container div {
    display: inline-block;
    margin: 5px;
}

.container div:nth-child(n+4):not(:nth-child(4):last-child) {
    background: red;
}

<div class="container">
<div>1</div>
<div>2</div>
</div>
<div class="container">
<div>1</div>
<div>2</div>
<div>3</div>
</div>
<div class="container">
<div>1</div>
<div>2</div>
<div>3</div>
<div>4</div>
</div>
<div class="container">
<div>1</div>
<div>2</div>
<div>3</div>
<div>4</div>
<div>5</div>
</div>
<div class="container">
<div>1</div>
<div>2</div>
<div>3</div>
<div>4</div>
<div>5</div>
<div>6</div>
</div>
<div class="container">
<div>1</div>
<div>2</div>
<div>3</div>
<div>4</div>
<div>5</div>
<div>6</div>
<div>7</div>
</div>

jsfiddle: https://jsfiddle.net/e9fgdeu1/

Answer 1

我认为只有一个选择器是不够的。但是可以使用以下选择器完成:

.container div:nth-child(n + 5),
.container div:nth-child(4):not(:last-child) {
  background: red;
}

.container div {
  display: inline-block;
  margin: 5px;
}

.container div:nth-child(n + 5),
.container div:nth-child(4):not(:last-child) {
  background: red;
}

<div class="container">
  <div>1</div>
  <div>2</div>
</div>
<div class="container">
  <div>1</div>
  <div>2</div>
  <div>3</div>
</div>
<div class="container">
  <div>1</div>
  <div>2</div>
  <div>3</div>
  <div>4</div>
</div>
<div class="container">
  <div>1</div>
  <div>2</div>
  <div>3</div>
  <div>4</div>
  <div>5</div>
</div>
<div class="container">
  <div>1</div>
  <div>2</div>
  <div>3</div>
  <div>4</div>
  <div>5</div>
  <div>6</div>
</div>
<div class="container">
  <div>1</div>
  <div>2</div>
  <div>3</div>
  <div>4</div>
  <div>5</div>
  <div>6</div>
  <div>7</div>
</div>