c++ - C++中的简单列表

Question

explicit list(
   const A& Al = A( )
);
explicit list(
   size_type n,
   const T& v = T( ),
   const A& Al = A( )
);
list(
   const list& x
);
list(
   const_iterator First,
   const_iterator Last,
   const A& Al = A( )
);

Answer 1

#include <list>
using namespace std;

list<Node> my_list;

int index = 0;
for ( list<Node>::iterator cursor = my_list.begin();
    it!= my_list.end(); ++ cursor, ++ index ) {
    cout << "index: " << index << “ value: “ << cursor->data() << endl;
}