我是编程新手，我遇到了一个我从未听说过的错误，如果我按下 A1 之后的任何东西，它就会崩溃 我收到错误消息“您的程序中引发了访问冲突(段错误)。” 我几乎完成了这个项目 这阻止了我 为什么我可以输入A1但不能输入A2等等
#include <iostream>
#include <iomanip>
#include <string>
#include <fstream>
#include <stdlib.h>
#include <sstream>
using namespace std;
//function prototype
void fill_array();//fill the array using data from the text file
string Candy_selection[16][4] = {""};//checks array for valid data
int main()
{
string code = "";
string name = "";
double price = 0.0;
double paid = 0.0;
int remaining = 3;
double change = 0.0;
bool item_bought = false;
string convertInt(int number);//converts string to int
fill_array();//fills array
for(int x = 0; x<16; x += 1)
{
cout << "The codes are "<<Candy_selection[x][0]<<endl;
}
while(code != "E5")
{
cout << "Enter the candy code: ";//ask for code for candy
cin >> code;
int x = 0;
while(x < 16 && item_bought == false )
{//checks if code matches up with a valid code
if(code == Candy_selection[x][0])//if code found
{
name = Candy_selection[x][1];//assigns name of candy to name
price = (double)atof(Candy_selection[x][2].c_str()); //convert to double
remaining = (int)atof(Candy_selection[x][3].c_str());//convert to int
if(remaining != 0)//if there is any of that candy left continue processing
{
cout << "You are buying a "<<name<<" The Cost is $"<<price<<endl;//tells how much the candy bar is
cout << "Please insert money $";
cin >> paid;
if(paid >= price) //makes sure the amount paid is atleast = to the candy bar
{
if(paid > price)
{
change = paid - price;//calculates change if any
}
remaining -= 1; //since candy was bought lowers teh amount remaining by one
Candy_selection[x][3] = convertInt(remaining);//converts to string and stores updated value in array
cout << fixed <<setprecision(2);
cout <<"You have bought a " <<name <<" for $"<<price <<" your change is $"<<change<<endl;
}else cout << "you didnt have enough money "<<endl;//not enough paid
}else cout << "This treat is sold out, please select another"<<endl;//remainder == 0
}else if(code == Candy_selection[16][0])//if code is not found in array
{
cout << "Code not found "<<endl;//code not found
}
item_bought = true;//acts as a sentinal value to get out of loop if item is bought
x+= 1;//moves to next array location
}
//reseteting values
code = "";
item_bought = false;
name = "";
price = 0.0;
paid = 0.0;
change = 0.0;
x = 0;
}
system("pause");
}
void fill_array()//fills array with data from text file
{
string candy_code = "";
string candy_name = "";
string candy_price = "";
string remaining_candy = "";
ifstream Candy;
Candy.open("Candy.txt");
if(Candy.is_open() == true)
{
while(Candy.eof() == false)
{
for(int y = 0;y < 16; y += 1)//puts the data in array then loops on next line then repeats
{
getline(Candy, candy_code, '#');//picking the code name from first field
getline(Candy, candy_name, '#');//picking the candy name from second field
getline(Candy, candy_price, '#');//picking the candy price from third field
getline(Candy, remaining_candy, '\n');//picking the candy limit in stalk from 4th field
//puts each entry in the array
Candy_selection[y][0] = candy_code;
Candy_selection[y][1] = candy_name;
Candy_selection[y][2] = candy_price;
Candy_selection[y][3] = remaining_candy;
}
}
Candy.close();
}else cout <<"cannot open data file to sync to array"<<endl;
}
string convertInt(int number)
{
stringstream ss;//create a stringstream
ss << number;//add number to the stream
return ss.str();//return a string with the contents of the stream
}
文本文件如下
A1#Jelly Beans#1.00#3
A2#Penut butter cup#1.00#3
A3#PB&J#1.00#3
A4#100 Grand bar#1.00#3
B1#Crackers#1.00#3
B2#gum#1.00#3
B3#gummy worm#1.00#3
B4#chocolot bar#1.00#3
C1#Honey bun#1.00#3
C2#Pretzels#1.00#3
C3#Cinnamin bun#1.00#3
C4#gobstocker#1.00#3
D1#pop corn#1.00#3
D2#krabby paddy#1.00#3
D3#chocolot frog#1.00#3
D4#mint#.25#3
最佳答案
code == Candy_selection[16][0]
这可能是它，您正在访问第 17 个元素，但您只有 16 个元素。
如果不是，您需要搜索类似的溢出、空访问等。使用调试器、gdb 或 visual studio 运行它
关于c++ - “An access violation (Segmentation Fault) raised in your program.”，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/18394945/