c++ - 如何将 char * buffer 转换为 unsigned short int * bufferSh

Question

如何将 char buffer 转换为 unsigned short int newBuffer？ 下面是我的代码:

另外，在生成的新缓冲区中，如何获取大小。 我正在读取 char 缓冲区中的图像文件，为了进一步处理，我想将此 char 转换为 unsigned short int *。 请有人帮我解决这个问题

FILE * pFile;
long lSize;
char * buffer;
size_t result;
pFile = fopen ( "d:\\IMG1" , "rb" );
if (pFile==NULL) {fputs ("File error",stderr); exit (1);}
// obtain file size:
fseek (pFile , 0 , SEEK_END);
lSize = ftell (pFile);
rewind (pFile);
// allocate memory to contain the whole file:
buffer = (char*) malloc (sizeof(char)*lSize);
if (buffer == NULL) {fputs ("Memory error",stderr); exit (2);}
// copy the file into the buffer:
result = fread (buffer,1,lSize,pFile);
if (result != lSize) {fputs ("Reading error",stderr); exit (3);}
/* the whole file is now loaded in the memory buffer. */
// terminate
fclose (pFile);

unsigned short int *shBuffer = (unsigned short int *)buffer;
int jp2shortsize = sizeof(*shBuffer); 
free (buffer);

Answer 1

最好在 C++ 中使用 reinterpret_cast 进行指针转换:

unsigned short int* ptrA = reinterpret_cast<unsigned short int*>(ptrB);

对于大小，您已经获得了它，因此您只需要对要转换为的类型的大小进行归一化:

int jp2shortsize = lSize * sizeof(char) / sizeof(unsigned short int);