以下代码:
enum Type {Prince, Princess, King, Queen, NumTypes};
enum Country {England, Belgium, Netherlands, NumCountries};
class Factory {
static const std::array<std::array<int, NumTypes>, NumCountries> probabilities;
static std::array<std::array<int, NumTypes>, NumCountries> initializeProbabilities() {
std::array<std::array<int, NumTypes>, NumCountries> p;
p[England] = {29, 60, 80, 100};
p[Belgium] = {31, 66, 81, 100};
p[Netherlands] = {25, 45, 90, 100};
return p;
}
};
const std::array<std::array<int, NumTypes>, NumCountries> Factory::probabilities = initializeProbabilities();
如果我更改枚举 Country 中元素的顺序是安全的,但是对于将来对枚举 Type 元素进行任何重新排序是不安全的。在不一一初始化所有 12 个元素的情况下避免该问题的最佳方法是什么?
最佳答案
为了避免对顺序的依赖,你应该这样写:
p[England][Prince]=29;
p[England][Princess]=60;
p[England][King]=80;
p[England][Queen]=100;
p[Belgium][Prince]=31;
p[Belgium][Princess]=66;
p[Belgium][King]=81;
p[Belgium][Queen]=100;
关于c++ - 初始化静态二维数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24986000/