我遇到了问题,我不确定如何解决。
这是我创建的一个搜索功能,但我从中收到了错误;
void guestSearch()
{
&Reservation::getfirstName;
&Reservation::getlastName;
&Date::getday;
&Date::getmonth;
&Date::getyear;
Hotelreservation reg;
reg.duration;
reg.occupants;
&Contact::getareaCode;
&Contact::getexchange;
&Contact::getline;
system("cls");
cout<<"Enter Line Number for the Guest you are searching for:";
cin>>line;
string line2= to_string(line);
line2.append(".txt");
ifstream filemain(line2);
while(firstName>>lastName>>day>>month>>year>>duration>>occupants>>areaCode>>exchange>>line)
{
int firstNameLength=firstName.size();
int lastNameLength=lastName.size();
int lengthTotal=firstName+lastName;
string result;
cout<< "Is this the correct Guest (y/n)"<<endl;
cout<<"Name"<<firstName<<" "<<lastName<<end;
cin>>result;
if(result=="y")
{
system("cls");
cout<<"Name";
for(int y = 1; y<lengthTotal; y++)
{
cout<< " ";
}
cout<<"Reservation Date";
for(int z=1; z<2; z++)
{
cout<< " ";
}
cout<<"Duration of Stay";
for(int x=1; x<2; x++)
{
cout<< " ";
}
cout<<"Occupants";
for(int u=1; u<2; u++)
{
cout<< " ";
}
cout<<"Contact Number";
for(int v=1; v<2; v++)
{
cout<< " ";
}
}
cout<<"Date Reservation was made:"<<day<<"/"<<month<<"/"<<year<<endl;
cout<<"Duration Of Stay:"<<duration<<endl;
cout<<"Occupants:"<<occupants<<endl;
cout<<"Contact Number:"<<areaCode<<"-"<<exchange<<"-"<<line<<endl;
}
}
我在 firstName ">>"
之后的 while 声明中收到一个错误,我得到这个:
IntelliSense: no operator ">>" matches these operands operand types are: std::string>>std::string"
最佳答案
你误解了这个概念,尽管可以通过 operator >>
链接多个 std::string
实例,但第一个对象应该是继承自 的类型std::istream
例如 ifstream fileman
在你的情况下:
while( fileman >> firstName >> lastName >> ... )
之所以有效,是因为您可以将该表达式视为:
while( fileman.operator>>( firstName ).operator>>( lastName ) ... )
并且因为 std::istream::operator>>
再次返回对 std::istream
的引用,所以链调用有效。
std::string
中没有这样的操作符
关于c++ - std::string>>std::string 没有运算符 ">>",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26911272/