C++ Card 相关程序将无法编译。 (运行时错误)

Question

有谁知道为什么我的程序会出现运行时错误并崩溃？我似乎无法弄清楚。似乎没有调试选项。它只是在启动时崩溃。请帮助我完整地回答我的问题并善待它。希望大家能帮帮我。

#include <cstdlib>
#include <iostream>
#include <ctime>
#include <math.h>
using namespace std;

class Card {
    private:
        string suit;
        string face;
        int number;

    public:
        Card (string cardsuit , int cardnumber){
            suit = cardsuit;
            number = cardnumber;
        }

        Card () {
            suit = "";
            number = 0;
        }

        void setcard (string cardsuit){
            suit = cardsuit;
        }

        void setnumber( int cardnumber){
            number = cardnumber;
        }

        void display() {
            if(number == 0) {
                cout << "" ;
            }
            else
                (cout << number << " of " << suit << endl)  ;
        }
};

int main(int argc, char *argv[])
{
    Card acard[52];

    for (int i = 0; i <= 13; i++){
        acard[i] = Card("Hearts " , i+1);
    }  

    for (int i = 0; i <= 13; i++) {
        acard[i+13] = Card("Diamonds " , i+1);
    }

    for (int i = 0; i <= 13; i++) {
        acard[i+26] = Card("Clubs " , i+1);
    }

   for (int i = 0; i <= 13; i++) {
        acard[i+39] = Card("Spades " , i+1);
    }

    for (int i = 0; i < 52; i++) {
        acard[i].display();
    }

    cout << endl;
    system("PAUSE");
    return EXIT_SUCCESS;
}

Answer 1

逻辑错误...

您在功能上用“方 block 1”覆盖了“红心 14”。您也可以对其余花色执行此操作。

acard[i] = Card("Hearts " , i+1);      // i is 13
acard[i+13] = Card("Diamonds " , i+1); // i is 0

写入超出数组末尾...

在最后一个 for 循环中，最后一次迭代在数组末尾之外写入:

acard[i+39] = Card("Spades " , i+1);   // i is 13

还有...

在 Card::display() 中将 cout 表达式放在圆括号中是很奇怪的。