c++ - 如何在嵌套循环中请求用户输入？

Question

我的任务是显示斐波那契数列，但同时询问用户他/她想在给定时间计算多少数。

他们让我引用的书中有一个例子。我认为代码中的几行更改可以解决我的问题，但我无法理解这段代码哪里出了问题。

int main()
{ 
    int NumsToCal = 5;

    cout << "How many numbers would you like to calculate?" << endl;
    cin >> NumsToCal;

    cout << " This program will calculate " << NumsToCal << " Fibonacci Numbers at a time" <<endl;

    int Num1 = 0, Num2 = 1;
    char WantMore = '\0';
    cout << Num1 << " " << Num2 << " " ;

    do 
    {
        for( int Index = 0; Index < NumsToCal; ++Index)
        {
            cout << Num1 + Num2 << " ";

            int Num2Temp = Num2;
            Num2 = Num1 + Num2;
            Num1 = Num2Temp;
        }
        cout <<  "Do you want more numbers (y/n)? " << endl;
        cin >> WantMore;

    } while (WantMore == 'y');

        cout << "Goodbye!" << endl;

    return 0;
}

Answer 1

Xsami 完全正确。您只需要再添加一行，例如:

cin>>NumstoCal;

尽管为了更清晰一点而改变输出内容的方式也不错。

这是我的代码: https://ideone.com/BXREP9