c++ - 有没有办法在 cout (C++) 中隐藏变量？

Question

我在弄清楚如何在 cout 函数中隐藏特定变量(如果可能的话)时遇到了问题。基本上我需要做一个数字猜谜游戏，这很容易，除非我们的老师希望我们像随机数学方程式那样来做。老实说，这仍然相当容易，除了我们必须这样做的方式是程序必须随机创建问题，然后随机选择要显示的 3 个数字之一，用户必须猜测另外两个缺失的数字。例如，如果程序选择 20 + 32 = 52，它可能会显示 __ + 32 = __。

我已经做到了那么远，但是我不知道如何制作它所以它会像那样显示，但仍然允许我像这样放线

    cout << num1 //Hidden << " + " << num2 << " = " << num3 //Hidden

但是就像我说的那样，我什至不知道这是否可行，否则我可能不得不重写整个程序。这是我目前所拥有的:

int main()
{
    int num1, num2, num3, random1, guess1, guess2;
    string play = "";

    cout << "Would you like to run the number guessing program? (enter yes or no): ";
    getline(cin, play);
    for (int i = 0; i < play.length(); i++)
    {
        play[i] = tolower(play[i]);
    }

    //Random seed
    srand(time(0));

    while (play == "yes")
    {
        //Generate random numbers and num3
        num1 = 1 + rand() % 50 + 1;
        num2 = 1 + rand() % 50 + 1;
        num3 = num1 + num2;
        int pickRandom[3] = { num1, num2, num3 };

        //Display random elements
        random1 = pickRandom[rand() % 3];

        if (random1 == num1){
            cout << "\nYour randomly generated number problem: " << num1 << " + " << "__" << " = " << "__" << endl;
        }
        if (random1 == num2){
            cout << "\nYour randomly generated number problem: " << "__" << " + " << num2 << " = " << "__" << endl;
        }
        if (random1 == num3){
            cout << "\nYour randomly generated number problem: " << "__" << " + " << "__" << " = " << num3 << endl;
        }
        //Get Guesses
        cout << "\nBased off of this information please make an educated guess as to what the two missing numbers are.";
        cout << "\n\nGuess for number 1 (between 1 and 100): ";
        cin >> guess1;
        while ((guess1 > 100) || (guess1 < 0))
        {
            cout << "\nSorry you need to enter an integer between 1 and 100" << endl;
            cout << "\nGuess for number 1 (between 1 and 100): ";
            cin >> guess1;
        }
        cout << "\n\nGuess for number 2 (between 1 and 100): ";
        cin >> guess2;
        while ((guess2 > 100) || (guess2 < 0))
        {
            cout << "\nSorry you need to enter an integer between 1 and 100" << endl;
            cout << "\nGuess for number 2 (between 1 and 100: ";
            cin >> guess2;
        }
        if (guess1 == )
    }

    return 0;
}

Answer 1

我认为您不能在cout 中隐藏变量。但是您可以使用变量而不是硬编码“__”。

例如，你可以简单地这样写:

  if(guessed_var1_correctly)
      var1 = num1
  else
      var1 = "__"

  if(guessed_var2_correctly)
      var2 = num2
  else
      var2 = "__"

  if(guessed_var3_correctly)
      var3 = num3
  else
      var3 = "__"

  cout << "\nYour randomly generated number problem: " << var1 << " + " << var2 << " = " << var3" << endl;

其中 var1、var2、var3 是输出变量。如果玩家猜对了，它会显示实际值 num1、num2 或 num3。如果没有，它只会显示“__”。