不持有一个以上账户的 C++ 银行应用程序

Question

您好，我一直在开发一个 C++ 银行应用程序，它应该能够在所有相关领域持有多个帐户。我遇到了一些问题:

• 在 Display 或 ShowInfo 函数中显示帐户信息时，不会显示名字的第一个字母和中间名的首字母。
• 创建帐户时，只能搜索最近的帐户并将其显示在显示数据中。我知道这需要一个数组才能实现，我只是不确定是否正确实现了这一点。

感谢您的帮助。感谢任何输入!

#include <stdlib.h>
#include <conio.h>
#include <iostream>
#include <string>

using namespace std;

class BankAccount{
    double Balance = 0.0;
    char ans;
    public:struct Name{
        char Last_Name[50];
        char First_Name[50];
        char Middle_Initial[5];
    }Name;
    public:struct Account{
        char Type[1];
        int Account_Number;
    }Account;
    public:
    void CreateAccount();
    void Withdraw();
    void Deposit();
    void Display();
    void ShowInfo();
    int Menu();

};

void BankAccount::CreateAccount(){
    do
    {
        cout << "\nEnter account number: ";
        cin >> Account.Account_Number;
        cout << "\nEnter the last name for the account: ";
        cin.ignore();
        cin.getline(Name.Last_Name, 50);
        cout << "\nEnter the first name for the account: ";
        cin.ignore();
        cin.getline(Name.First_Name, 50);
        cout << "\nEnter the Middle initial for the account: ";
        cin.ignore();
        cin.getline(Name.Middle_Initial, 5);
        cout << "\nEnter the type of account (C/S) : ";
        cin >> Account.Type;
        cout << "\nEnter the initial balance of the account: ";
        cin >> Balance;
        cout << "\n\nAccount Created.";
        cout << "\n\nCreate new account? (Y/N) : ";
        cin >> ans;

        while (ans != 'Y' && ans != 'N'){
            cout << "Invalid input. Create new account? (Y/N) : ";
            cin >> ans;
        }
        cout << endl;
    } while (ans != 'N');
};
void BankAccount::Withdraw(){
    int actNum;
    double amount;
    cout << "Enter the account number for the account that you wish to withdraw funds: ";
    cin >> actNum;
    if (actNum == Account.Account_Number){
        cout << "Enter the amount you would like to withdraw: ";
        cin >> amount;
        Balance = Balance - amount;
    }
    else if (actNum != Account.Account_Number){
        cout << "No account found under that number! Try again!";
    }

}
void BankAccount::Deposit(){
    int actNum;
    double amount;
    cout << "Enter the account number for the account that you wish to deposit funds: ";
    cin >> actNum;
    if (actNum == Account.Account_Number){
        cout << "Enter the amount you would like to deposit: ";
        cin >> amount;
        Balance = Balance + amount;
    }
    else if (actNum != Account.Account_Number){
        cout << "No account found under that number! Try again!";
    }
}
void BankAccount::Display(){
    int actNum;
    cout << "Enter the account number for the account that you wish to display account information for: ";
    cin >> actNum;
    if (actNum == Account.Account_Number){
        cout << "Account details for " << Name.First_Name << " " << Name.Middle_Initial << " " << Name.Last_Name << "'s account: " << endl;
        cout << "Account Number: " << Account.Account_Number << endl;
        cout << "Account Type (Checking / Savings): " << Account.Type << endl;
        cout << "Account Balance:  $" << Balance << endl;
    }
    else if (actNum != Account.Account_Number){
        cout << "No account found under that number! Try again!";
    }

}
void BankAccount::ShowInfo(){
    cout << "Account details for " << Name.First_Name << " " << Name.Middle_Initial << " " << Name.Last_Name << "'s account: " << endl;
    cout << "Account Number: " << Account.Account_Number << endl;
    cout << "Account Type (Checking / Savings): " << Account.Type << endl;
    cout << "Account Balance:  $" << Balance << endl;    

}

int main(int argc, char *argv){
    BankAccount ob;
    char ch;

    cout << "Welcome to Console Banking Application V 1.0!";
    cout << "\nSelect an item from the list below by entering the corresponding letter.";
    do{
        cout << "\n\n A. Create Account \n B. Withdraw \n C. Deposit \n D. Show Account Details \n\n Q. Exit Application\n\n";
        ch = ob.Menu();
        switch (ch){
        case 'A':
        case 'a': ob.CreateAccount();
            ob.ShowInfo();
            break;
        case 'B': 
        case 'b': ob.Withdraw();
            break;
        case 'C':
        case 'c': ob.Deposit();
            break;
        case 'D':
        case 'd': ob.Display();
            break;
        case 'Q':
        case 'q': ob.ShowInfo();
                  exit(1);
            break;
        }

    } while (1);
}
int BankAccount::Menu(){
    char ch;
    cout << "Select an option: ";
    cin >> ch;
    return ch;
}

Answer 1

简单的答案是:您只有一个银行账户。

如果您查看主函数，您会创建一个且只有一个 BankAccount。您可能会猜到，一个 BankAccount 不能用于表示多个 BankAccount(除了 SoAs)。

因此，您需要一个 BankAccounts 的数组。它是这样的:

BankAccount obs[10];

现在您有 10 个 BankAccounts，不会再多了。因此，每次您想要创建一个新的 BankAccount 时，只需确保您在当前未使用的数组中的 BankAccount 上创建它。

obs[0].CreateAccount();
obs[0].ShowInfo();
obs[0].Deposit();
//Make a new account
obs[1].CreateAccount();
...

更进一步，让我们考虑一下您有 10 个 BankAccounts 的事实，只有 10 个。现在这不是很广泛，是吗？什么银行只有 10 个可用账户？可能会在适当的时候倒闭。

天真的解决方案是添加更多。 50、100，甚至 1000。但是您真的要每次都返回并更新该数字吗？这太乏味了。

幸运的是，我们可以使用一个方便的容器:

#include <vector>
...
std::vector<BankAccount> obs;
...

这基本上是一个在需要时自动展开的数组。我不会详细介绍如何使用 vector ，因为我相信您自己可以轻松学会这样做。但是，我会把这个 link 留给你这样您就知道可以从哪里开始。