c++ - C/C++ 优化编译器因使用模板而损坏

Question

我有 Foo 和 Bar 如下:

Foo.h

#include <list>

using namespace std;

class Foo
{
private:
    template <typename BarT>
    list<BarT*> barT_lst;

public:
    template <typename BarT>
    Foo(void);

    ~Foo(void);
};

Foo.cpp

#include "Foo.h"

template <typename BarT>
Foo::Foo(void)
{
}

Foo::~Foo(void)
{
}

酒吧.h

class Bar
{
public:
    Bar(void);
    ~Bar(void);
};

Bar::Bar(void)
{
}

Bar::~Bar(void)
{
}

和 main()

#include "Foo.h"
#include "Bar.h"

int _tmain(int argc, _TCHAR* argv[])
{
    Foo<Bar> foo = Foo<Bar>();
    return 0;
}

我使用的是 VC++2008。每次构建项目时，它都会显示错误:

1>------ Build started: Project: Test, Configuration: Debug Win32 ------
1>Compiling...
1>Test.cpp
1>c:\users\duong2179\documents\visual studio 2008\projects\test\test\foo.h(12) : fatal error C1001: An internal error has occurred in the compiler.
1>(compiler file 'msc1.cpp', line 1411)
1> To work around this problem, try simplifying or changing the program near the locations listed above.
1>Please choose the Technical Support command on the Visual C++ 
1> Help menu, or open the Technical Support help file for more information
1>Build log was saved at "file://c:\Users\duong2179\Documents\Visual Studio 2008\Projects\Test\Test\Debug\BuildLog.htm"
1>Test - 1 error(s), 0 warning(s)
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

这看起来很奇怪。请帮忙!

Answer 1

从编译器获取访问冲突不应该真的发生，升级编译器会很好。

但是您的代码也是非法的。如果你打算写 Foo<Bar> foo;然后 Foo需要是模板，例如:

template<typename BarT>
class Foo
{
    std::list<BarT *> barT_lst;
public:
    Foo();
    ~Foo();
};

template<typename BarT>
Foo<BarT>::Foo() 
{
    // constructor code here
}

注意:这个类可能违反了Rule of Three ，你不应该有原始指针的容器，除非这些指针不拥有它们所指向的内容。 (在这种情况下，您不需要析构函数)。