<分区>
在 C++ 中，我试图在 switch 语句之后使用 if 语句。我如何运行 if 因为它没有运行它。开关只是运行。
输出是:
492.5
490
487.5
485
482.5
480
477.5
475
472.5
470
467.5
下一个输出减少-2.5。
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
double A(5), B(5), C(0), D(7.5), E(20), V(495), F, G, H, I, J, K, L, M, N, O, P;
for (int t = 0; t <= 10; t = t + 1)
{
switch (t)
{
case 0:
F = A + B + C + D - E + V;
cout << F << endl;
break;
case 1:
G = A + B + C + D - E + F;
cout << G << endl;
break;
case 2:
H = A + B + C + D - E + G;
cout << H << endl;
break;
case 3:
I = A + B + C + D - E + H;
cout << I << endl;
break;
case 4:
J = A + B + C + D - E + I;
cout << J << endl;
break;
case 5:
K = A + B + C + D - E + J;
cout << K << endl;
break;
case 6:
L = A + B + C + D - E + K;
cout << L << endl;
break;
case 7:
M = A + B + C + D - E + L;
cout << M << endl;
break;
case 8:
N = A + B + C + D - E + M;
cout << N << endl;
break;
case 9:
O = A + B + C + D - E + N;
cout << O << endl;
break;
case 10:
P = A + B + C + D - E + O;
cout << P << endl;
break;
case 11:
if (B = B + 5)
{
F = A + B + C + D - E + V;
G = A + B + C + D - E + F;
H = A + B + C + D - E + G;
I = A + B + C + D - E + H;
J = A + B + C + D - E + I;
K = A + B + C + D - E + J;
L = A + B + C + D - E + K;
M = A + B + C + D - E + L;
N = A + B + C + D - E + M;
cout << F << endl;
cout << G << endl;
cout << H << endl;
cout << I << endl;
cout << J << endl;
cout << K << endl;
cout << L << endl;
cout << M << endl;
cout << N << endl;
}
}
}
system("pause");
}