c++井字棋程序

标签 c++ tic-tac-toe

<分区>

所以我一直在构建一个 Tic-Tac-Toe 程序,目前它仍在进行中。到目前为止我没有收到任何构建错误,但我目前遇到的主要问题是当玩家 1 输入他们的第一个数字时程序就关闭了。我认为这是因为 Input() 函数,但在查看代码大约 3 次后,我一头雾水,不知道是什么原因造成的。这是相关代码:

#include <iostream>
using namespace std;


char acBoard[3][3] = { '1', '2', '3', '4', '5', '6', '7', '8', '9' };
char cPlayerCharacter = '0';
int iChoice = iChoice + 1;




void DisplayBoard()
{
    system("cls");
    cout << ' ' << acBoard[0][0] << " | " << acBoard[0][1] << " | " << acBoard[0][2] << endl;
    cout << "---|---|---" << endl;
    cout << ' ' << acBoard[1][0] << " | " << acBoard[1][1] << " | " << acBoard[1][2] << endl;
    cout << "---|---|---" << endl;;
    cout << ' ' << acBoard[2][0] << " | " << acBoard[2][1] << " | " << acBoard[2][2] << endl;
}

char win()
{
    if (acBoard[0][0] && acBoard[0][1] && acBoard[0][2] == 'X' ||
        acBoard[1][0] && acBoard[1][1] && acBoard[1][2] == 'X' ||
        acBoard[2][0] && acBoard[2][1] && acBoard[2][2] == 'X' ||
        acBoard[0][0] && acBoard[1][0] && acBoard[2][0] == 'X' ||
        acBoard[0][1] && acBoard[1][1] && acBoard[2][1] == 'X' ||
        acBoard[0][2] && acBoard[1][2] && acBoard[2][2] == 'X' ||
        acBoard[0][0] && acBoard[1][1] && acBoard[2][2] == 'X' ||
        acBoard[2][0] && acBoard[1][1] && acBoard[2][0] == 'X')
        return 'X';

    if (acBoard[0][0] && acBoard[0][1] && acBoard[0][2] == '0' ||
        acBoard[1][0] && acBoard[1][1] && acBoard[1][2] == '0' ||
        acBoard[2][0] && acBoard[2][1] && acBoard[2][2] == '0' ||
        acBoard[0][0] && acBoard[1][0] && acBoard[2][0] == '0' ||
        acBoard[0][1] && acBoard[1][1] && acBoard[2][1] == '0' ||
        acBoard[0][2] && acBoard[1][2] && acBoard[2][2] == '0' ||
        acBoard[0][0] && acBoard[1][1] && acBoard[2][2] == '0' ||
        acBoard[2][0] && acBoard[1][1] && acBoard[2][0] == '0')
        return '0';

    return 'd';
}


void Input()
{
    cin >> iChoice;
    switch (iChoice)
    {
    case 1:
        acBoard[0][0] = cPlayerCharacter;
        break;
    case 2:
        acBoard[0][1] = cPlayerCharacter;
        break;
    case 3:
        acBoard[0][2] = cPlayerCharacter;
        break;
    case 4:
        acBoard[1][0] = cPlayerCharacter;
        break;
    case 5:
        acBoard[1][1] = cPlayerCharacter;
        break;
    case 6:
        acBoard[1][2] = cPlayerCharacter;
        break;
    case 7:
        acBoard[2][0] = cPlayerCharacter;
        break;
    case 8:
        acBoard[2][1] = cPlayerCharacter;
        break;
    case 9:
        acBoard[2][2] = cPlayerCharacter;
        break;
    }
}


int main()
{
    do
    {
        DisplayBoard();
        cout << "Enter a Number Player " << cPlayerCharacter << ": ";
        Input();
        if (cPlayerCharacter = '0')
        {
            cPlayerCharacter = 'X';
        }
        else cPlayerCharacter = '0';
    } while (!win);

    if (win() == 'd')
    {
        cout << "It's a draw";
    }

    if (win() == '0')
    {
        cout << "Nought wins";
    }

    if (win() == 'X')
    {
        cout << "Cross wins";
    }
}

我觉得解决方案就在我面前,但我就是看不到。任何帮助,将不胜感激。谢谢。

最佳答案

while (!win); 应该是 while (!win()); 才能实际调用该函数。否则,您实际上只是在评估函数是否存在。

关于c++井字棋程序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41047445/

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