c++ - 如何将 'const char *' 转换为 'const unsigned char *'

Question

如何将'const char *'转换为'const unsigned char *'

 bool AES(const uint8_t *Data, size_t Size) {  
     std::string s(reinterpret_cast<const char *>(Data), Size);
     AES_cbc_encrypt(s.c_str(), enc_out, Size, &enc_key, iv, AES_ENCRYPT);
    }

程序编译时出现的错误

candidate function not viable: no known conversion from 'const char *' to 'const unsigned char *'
      for 1st argument
void AES_cbc_encrypt(const unsigned char *in, unsigned char *out,

我试过了，不行

std::string s(reinterpret_cast<const unsigned char *>(Data), Size);

Answer 1

uint8_t, if it's available , 只是 unsigned char 的类型定义。因此，你可以这样做:

 bool AES(const uint8_t *Data, size_t Size) {  
     AES_cbc_encrypt(Data, enc_out, Size, &enc_key, iv, AES_ENCRYPT);
 }

请注意，您可能还应该在函数中返回一些内容。