c++ - 尝试选择文本颜色

Question

我正在尝试制作一个 C++ 控制台应用程序，用户可以在其中更改文本的颜色，但它会循环显示每种颜色并以原始颜色结束。这是我目前拥有的。感谢您的帮助。

while (strcmp(clrChoice, "nochange") != 0) {
    break;
}

while (strcmp(clrChoice, "gray") != 0) {
    system("COLOR 8");
    break;
}

while (strcmp(clrChoice, "blue") != 0) {
    system("COLOR 1");
    break;
}

while (strcmp(clrChoice, "lightblue") != 0) {
    system("COLOR 9");
    break;
}

while (strcmp(clrChoice, "green") != 0) {
    system("COLOR 2");
    break;
}

while (strcmp(clrChoice, "lightgreen") != 0) {
    system("COLOR A");
    break;
}

while (strcmp(clrChoice, "aqua") != 0) {
    system("COLOR 3");
    break;
}

while (strcmp(clrChoice, "lightaqua") != 0) {
    system("COLOR B");
    break;
}

while (strcmp(clrChoice, "red") != 0) {
    system("COLOR 4");
    break;
}

while (strcmp(clrChoice, "lightred") != 0) {
    system("COLOR C");
    break;
}

while (strcmp(clrChoice, "purple") != 0) {
    system("COLOR 5");
    break;
}

while (strcmp(clrChoice, "lightpurple") != 0) {
    system("COLOR D");
    break;
}

while (strcmp(clrChoice, "yellow") != 0) {
    system("COLOR 6");
    break;
}

while (strcmp(clrChoice, "lightyellow") != 0) {
    system("COLOR E");
    break;
}

while (strcmp(clrChoice, "white") != 0) {
    system("COLOR 7");
    break;
}

while (strcmp(clrChoice, "brightwhite") != 0) {
    system("COLOR F");
    break;
}

我在 Windows 10 上运行 Visual Studio 2015。

Answer 1

对于发布的代码，结果将始终是颜色 7 或颜色 E:

• 对于任何字符串，与“brightwhite”不同的是 F，
• 对于“brightwhite”字符串，它将是 7。

你可能想要这个:

if (strcmp(clrChoice, "gray") == 0) {
    system("COLOR 8");
} else if (strcmp(clrChoice, "blue") == 0) {
    system("COLOR 1");
}
..........