c++ - 是否 = 在 lambda 的捕获列表中捕获 this 指针

Question

我现在有这样的东西

void foo::setup()
{
        //this->setSubTitleText("Summary");
        button("ok")->onPress = [=](Mtype*)
        {
            this->bar(this); //Why is the this pointer being recognized here?
        };

}

lambda 捕获子句中的 = 是否提供对 this 指针的访问。在我的情况下是？我的印象是使用 this 指针，我需要像

一样显式捕获它

        button("ok")->onPress = [=,this](Mtype*)
        {
            this->bar(this); //Why is the this pointer being recognized here?
        };

有什么建议吗？

Answer 1

我认为cppreference.com非常明确地声明:

Lambda capture

The captures is a comma-separated list of zero or more captures, optionally beginning with the capture-default. The only capture defaults are

& (implicitly capture the odr-used automatic variables by reference) and

= (implicitly capture the odr-used automatic variables by copy).

The current object (*this) can be implicitly captured if either capture default is present. If implicitly captured, it is always captured by reference, even if the capture default is =.