我想替换 QDockWidget* 的小部件 (QWidget*),但调用 setWidget() , 删除以前的小部件。如何防止这种删除?
QDockWidget* dw = new QDockWidget;
QWidget* tw1 = new TestWidget;
QWidget* tw2 = new TestWidget;
dw->setWidget(tw1);
dw->setWidget(tw2); // tw1 deleted here
delete dw;
// I want to use tw1 here, but it died
TestWidget 只是一个检查删除时刻的测试:
class TestWidget : public QWidget {
public:
TestWidget(QWidget* parent = nullptr)
: QWidget(parent)
{
cout << "TestWidget() " << this << endl;
}
~TestWidget() override {
cout << "~TestWidget() " << this << endl;
}
};
最佳答案
QDockWidget* dw = new QDockWidget;
QWidget* tw1 = new TestWidget;
QWidget* tw2 = new TestWidget;
dw->setWidget(tw1);
dw->setWidget(tw2);
tw1->setParent(0);
delete dw; // dw and tw2 deleted here, but not tw1
关于c++ - 替换 QDockWidget 的小部件而不删除以前的,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48927197/