C++ 创建类时出错

Question

我是 c++ 的新手，直到今天才创建自己的类。我不喜欢发布代码供人们正常审查，但我的截止日期很紧，需要编译我的代码。我收到三个错误:

-错误:比之前的声明`RobotDeadReckoner::RobotDeadReckoner() throw ()'

-此行有多个标记 - 错误:RobotDeadReckoner::RobotDeadReckoner()' 的声明抛出不同 异常(exception) - 错误:隐式声明的定义RobotDeadReckoner::RobotDeadReckoner()'

-错误:类中没有声明RobotDeadReckoner::~RobotDeadReckoner()'成员函数RobotDeadReckoner'

代码如下:

#include <cmath>
#include "WPILib.h"


class RobotDeadReckoner
{//<---------------------Error
public:
    float getX();
    float getY();
    float getHeading();
private:
    Encoder *encoder1;//Encoder1 (Left Transmision while looking from the back)
    Encoder *encoder2;//Encoder2 (Right Transmision while looking from the back)
    int wheelRadius;//Wheel Radius (Center Wheel)
    float axleWidthCenterToCenter;
    int encoderTicksPerRotation;
    int transmitionSprocketTeeth;
    int wheelSprocketTeeth;
    int ticksPerRotation; //ticks per rotation of wheel
    float encoderTicks1;
    float encoderTicks2;
    float pi;
};

RobotDeadReckoner::RobotDeadReckoner()
{//<---------------------Error
    wheelRadius = 4;//Wheel Radius (Center Wheel)
    axleWidthCenterToCenter = 30+(7/8);
    encoderTicksPerRotation = 360;
    transmitionSprocketTeeth = 12;
    wheelSprocketTeeth = 26;
    ticksPerRotation = (wheelSprocketTeeth/transmitionSprocketTeeth)*encoderTicksPerRotation; //ticks per rotation of wheel

    encoderTicks1 = encoder1->Get();
    encoderTicks2 = encoder2->Get();

    pi = atan(1)*4;
}

float RobotDeadReckoner::getX()
{
    float x = wheelRadius*cos(getHeading())*(encoderTicks1+encoderTicks2)*(pi/ticksPerRotation);
    return x;
}

float RobotDeadReckoner::getY()
{
    float y = wheelRadius*sin(getHeading())*(encoderTicks1+encoderTicks2)*(pi/ticksPerRotation);
    return y;
}

float RobotDeadReckoner::getHeading()
{
    float heading = (2*pi)*(wheelRadius/axleWidthCenterToCenter)*(encoderTicks1-encoderTicks2);
    return heading;
}

RobotDeadReckoner::~RobotDeadReckoner()
{ //<---------------------Error

}

我确信这是一些愚蠢的简单的东西我不知道 c++ 但任何帮助将不胜感激!

Answer 1

definition of implicitly-declared RobotDeadReckoner::RobotDeadReckoner()

这是最大的线索。您还没有声明RobotDeadReckoner() 的构造函数，您只是定义它。如果您不提供默认构造函数，编译器将为您提供一个，因此“隐式声明”。参见 What is The Rule of Three? .

no RobotDeadReckoner::~RobotDeadReckoner()' member function declared in classRobotDeadReckoner'

析构函数也是如此。

将以下内容添加到您的类声明的(public: 部分):

RobotDeadReckoner();
virtual ~RobotDeadReckoner();