c++ - 指点功课

Question

如果有人能帮我完成这个并指出必须做些什么才能使程序运行，那就太好了。

-询问用户想输入多少天从1-365(验证)

-询问-60 到 90 摄氏度之间每一天的温度(循环，验证)

-将每个值转换为华氏度(函数)

-输出结果(函数)

问题

-用户应该输入一个整数摄氏度数，一个整数但它会转换为双华氏度数 前任。 4 摄氏度转换为 39.20 华氏度

• 对于这段代码...

  cout << "当天的摄氏温度 "<< i+1 << ": ";

  *(天 + 1) = GetValidInt("", TEMP_MIN, TEMP_MAX);

它在新的一行输出并等待输入...我怎样才能让它在同一行等待输入？

    #include <IOSTREAM> // input/outout stream
    #include <IOMANIP>  // for setw manipulator
    #include <CFLOAT>   // for limits of a double DBL_MIN and DBL_MAX
    #include <CLIMITS>  // for limits of a int INT_MIN and INT_MAX

    using namespace std;

    //Function Prototypes
    double GetValidDouble(string prompt = "", const double MIN = DBL_MIN, const double MAX = DBL_MAX);
    int GetValidInt(string prompt = "", const int MIN = INT_MIN, const int MAX = INT_MAX);
    int outputFunc (int*);
    double calcCelsius(double*);
    int main() {
            //Constants
            const int TEMP_MIN = -90;
            const int TEMP_MAX = 60;
            const int DAYS_MIN = 1;
            const int DAYS_MAX = 365;
            //Pointer
            int numDays;
            int *days;
            //Determine the number of days to get input for
            //Validation - Must be numeric || Between 1 - 365
            numDays = GetValidInt("How many days do you wish to enter? ", DAYS_MIN, DAYS_MAX);

            //Array Allocation
            cout << "TEMPRETURE REPORTER" << endl;
            cout << "====================" << endl;
            cout << "Please enter the tempreture for each day." << endl;
            try{
                    days = new int[numDays];
                        for(int i = 0; i < numDays; i++){
                            cout << "Celsius temperature for Day " << i+1 << " : ";
                            *(days + 1) = GetValidInt("", TEMP_MIN, TEMP_MAX);
                            //Validation - Between -90.00C and 60.00C
                        }
                        //for loop
                        for(int i = 0; i < numDays; i++){
                                cout << "" << outputFunc(&days);
                              }
                        //output function
                    delete[] days;
                }
            catch(bad_alloc){
                    cout << "\nCould not allocate that amount memory.";
                }
            cout << endl << endl;
            system("pause");
            return 0;
            }
            //An inline function is a function upon which the compiler has been requested to perform inline expansion. 
            //In other words, the programmer has requested that the compiler insert the complete body of the function 
            //in every place that the function is called, rather than generating code to call the function in the one place it is defined.
            inline double calcCelsius(double* celsius){
                double fahrenheit = 0;
                fahrenheit = (celsius*9/5)+32;
                return fahrenheit;
            }
            //Output Function
            int outputFunc (int* days){
                double fahrenheit = 0;
                //PROCESS
                //double     //&days int
                fahrenheit = calcCelsius(&days); //Calling calcCelsius
                //OUTPUT
                cout << right << setw(15) << "Day " << numDays << setw(10) << fahrenheit << char(248) << "F" << setw(10) << numDays << char(248) << "C" << endl;
            }
            double GetValidDouble(string prompt, const double MIN, const double MAX){
               double validNumber = 0.0; // holds the user input
               string rubbish;           // holds garbage input.

               cout << endl << prompt << " "; 
               cin >> validNumber;       // try to get input
               if(cin.fail()){           // if user input fails...
                   cin.clear();              // reset the cin object
                   cin >> rubbish;           // cleans garbage from cin.

                   // report the problem to the user.
                   cerr << "\nInvalid input. Please try again and enter a numeric value.\n";
                   // Try again by calling the function again (recursion)
                   validNumber = GetValidDouble(prompt, MIN, MAX);
               } 
               else if(validNumber < MIN || validNumber > MAX){// if value is outside range...
                   // report the problem to the user.
                   cerr << "\nInvalid input. Please try again and enter a value between "
                        << MIN << " and " << MAX << ".\n";
                   // Try again by call the function again (recursion)
                   validNumber = GetValidDouble(prompt, MIN, MAX);
               }
               return validNumber; // returns a valid value to the calling function.
            }
            int GetValidInt(string prompt, const int MIN, const int MAX){
                   double validNumber = 0.0; // holds the user input
                   validNumber = GetValidDouble(prompt, MIN, MAX); // get a number
                   if((int) validNumber < validNumber) // if the value is not a whole number...
                   {
                       cerr << "\nInvalid input. Please try again and enter a whole number.\n";
                       // Try again by calling the function again (recursion)
                       validNumber = GetValidInt(prompt, MIN, MAX);
                   }
                   return (int) validNumber; // returns a valid value to the calling function.
            }

Answer 1

您在请求数字之前输出一个换行符:

  cout << endl << prompt << " ";  // Output a line break ????
  cin >> validNumber;       // try to get i

只需删除上面的第一行。