c++ - 读取不同的输入类型 C++

Question

我正在尝试创建一个学生对象，该对象采用姓名、ID、电子邮件和三个整数等级。

我的代码很简单，如下:

studentObj* newStudent = new studentObj;

cout << "Student First Name: ";
getline(cin, newStudent->name);
cout << "Student ID: ";
getline(cin, newStudent->id);
cout << "Student Email: ";
getline(cin, newStudent->email);
cout << "Grade 1: ";
cin >> newStudent->gradeOne;
cout << "Grade 2: ";
cin >> newStudent->gradeTwo;
cout << "Term Grade: ";
cin >> newStudent->termGrade;

cout << "Student Name: " + newStudent->name << endl;
cout << "Student ID: " + newStudent->id << endl;
cout << "Student Email: " + newStudent->email << endl;
cout << "Grade 1: " + newStudent->gradeOne << endl;
cout << "Grade 2: " + newStudent->gradeTwo << endl;

我以为这会完美运行，但不幸的是事实并非如此。混合 getline() 似乎是个问题和 cin .

输出是:

Student Name: Test Tester
Student ID: abcdef
Student Email: email@test.com
rade 1:
ade 2:
m Grade: 

我试过添加 cin.ignore(numeric_limits<streamsize>::max(),'\n');在一些地方，但没有运气。有什么建议么？ `

Answer 1

您不能将字符串文字添加到整数(好吧，您可以，但在您的情况下您不会得到任何有意义的东西 - 您将进行偏移 - 因此字符串输出将是 rade 1: 因为 "Grade 1"+ 1 将指向字符串文字 rade 1)。

cout << "Student Name: " << newStudent->name << endl;
cout << "Student ID: " << newStudent->id << endl;
cout << "Student Email: " << newStudent->email << endl;
cout << "Grade 1: " << newStudent->gradeOne << endl;
cout << "Grade 2: " << newStudent->gradeTwo << endl;