Book Administrator::bookDetails()
{
Book book;
list<Book> books;
string title;
string author;
int ISBN;
string userInput;
while (userInput != "q")
{
cout << "Would you like to enter a book?" << endl;
cin >> userInput;
if (userInput == "yes")
{
cout << "What is the title of the book you want to enter?" << endl;
cin >> title;
cout << "What is the author of the book you want to enter?" << endl;
cin >> author;
cout << "What is the ISBN of the book you want to enter?" << endl;
cin >> ISBN;
book.setTitle(title);
book.setAuthor(author);
book.setISBN(ISBN);
books.push_back(book);
}
list<Book>::iterator pos;
pos = books.begin();
for (pos = books.begin(); pos != books.end(); pos++)
{
//There error is produced here
cout << *pos << "\n";
}
}
return book;
}
这是我的管理类的 bookDetails
函数。它循环遍历并询问书名、作者和 ISBN 号,完成后将书推送到列表中。
这在我调试时似乎工作正常,但当我尝试使用迭代器打印每本书的详细信息时出现错误。
有人可以帮我吗? 谢谢
最佳答案
您需要实现 operator<<
对于 Book
std::ostream operator<<(std::ostream& os, const Book& book)
{
os << book.title << " " << book.author; // print out other information
return os;
}
关于c++ - 打印列表中的元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20156352/